54 mL Ba(OH)2x(0.101 mol Ba(OH)2/1000 mL) x (2 mol OH-/ 1 mol Ba(OH)2 ) = 0.0109 mol OH-
0.0109 mol OH-x (1mol HCl/ 1 mol OH- ) = 0.0109 mol HCl
0.109 mol HCl/(0.130 mol/L HCl) = 0.0839 L HCl
0.0839 L HCl * 1000mL = 83.9 mL of 0.130 M HCl
Answer:
Mass percent of Mn is 34.76 %
Explanation:
<em>Mass percent</em> of an element is the mass of that element divided by the total mass of the elements forming that compound (or molecular mass.
So,
Mass percent of Mn will be given as,
%Mn = Atomic Mass of Mn / Molecular Mass of KMnO₄ × 100
So,
Atomic Mass of Mn = 54.94 g/mol
Molecular Mass of KMnO4 = 158.034 g/mol
Putting values in above formula,
%Mn = 54.94 g/mol ÷ 158.034 g/mol × 100
%Mn = 34.76 %
Answer:
So, Luke and Sian has to increase the pH of the soil by adding base to it.
Explanation:
The pH is defined as the negative logarithm of the hydrogen ion concentration in their aqueous solution.
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
- With increase in hydrogen ion concentration the pH value decreases.
- With decrease in hydrogen ion concentration the pH value increases.
The pH of the soil after testing it on a kit comes out be 5.0, but they both need pH of the soil to 6.5.
Comparison of pH of soil:
= 5.0 < 6.5
= High hydrogen ion concentration > High hydrogen ion concentration
So, Luke and Sian has to increase the pH of the soil by adding base .Doing so will decrease the hydrogen ion concentration in the soil (where as addition of acid lower the pH of soil).
Answer:
The standard enthalpy of combustion of solid urea ((CO(NH2)2) is -632 kJ mol-1 at 298 K and its standard molar entropy is 104.60 J K-1 mol-1
Explanation: