Answer:
the fisrt one is y=1/2x
the second one is y=x+11
the third one is y= x^3
fourth on is y= ^3 checkmark x
Step-by-step explanation: your welcome
Answer:
True?
Step-by-step explanation:
I think its true but I'm not 100% sure so I would go with true. Try thinking of your past problems that you used and think about that maybe? But in then mean time, I would go with True
slope = (25-4)/(30-10)
slope = 21/20
slope =21/20
using point slope form
y-y1 = m(x-x1)
y-4 = 21/20 (x-10)
y = 21/20x -21/2 +4
y = 21/20 x -21/2 +8/2
y = 21/20x -13/2
let x=40
y = 21/20 (40) -13/2
y = 42-13/2
y = 35.5 games
If we round the slope to 1
slope =1
using point slope form
y-y1 = m(x-x1)
y-4 = 1 (x-10)
y = 1x -10 +4
y = x -6
let x=40
y = 40-6
y = 34 games
You will have to use trig to solve this:
The side you have is adjacent to the known angle
The side you are looking for is opposite the known angle
^^^This means you need to use tan:
tan(24) = 
.445222 =
^^^input tan(24) into calculator, then multiply 12 to both sides to isolate and solve for x
5.3 ≈ x
Hope this helped!
Equation a^2 + b^2 = c^2
c = longest side, unknown
The answer is D.
12^2 + 10^2 = c^2
