You can find the segment congruent to AC by finding another segment with the same length. So first, you need to find the length of AC.
C - A = AC
0 - (-6) = AC Cancel out the double negative
0 + 6 = AC
6 = AC
Now, find another segment that also has a length of 6.
D - B = BD
2 - (-2) = BD Cancel out the double negative
2 + 2 = BD
4 = BD
4 ≠ 6
E - B = BE
4 - (-2) = BE Cancel out the double negative
4 + 2 = BE
6 = BE
6 = 6
So, the segment congruent to AC is B. BE .
Step-by-step explanation:
A portion of the Quadratic Formula proof is shown. Fill in the missing statement. Statements Reasons x² + x + b 4ac 4a? b? 4a² Find a common denominator on the right side of the equation a 2a X? + b 2a b? =4ac 4a? Add the fractions together on the right side of the equation a b2 - 4ac x+ Rewrite the perfect square trinomial on the left side of the equation as a binomial squared 2a 4a 2 Take the square root of both sides of the equation Vb -4ac x+ b 2a + 4a b - 4ас X + 2a + 4a 4ac + 2a 4a 1o ano 4a
Answer:
Y=-2/3+4
Step-by-step explanation:
The slope of the equation can be solved with
2-4/3-0 y2-y1 divide by x2-x1 which gives 3/2 and the y intercept the point at which the slope hits the y intercept which is 4. Also the slope is negative as it’s pointed downwards.
when there is no number with redical sign here it is equivalent to the exponent " 1/2 "
but when it is 3 under redical x that means it is x^1/3
In first one 8 ^(9/2) is same as ( redical 8 ) ^9
In part B it is (3 under redical 125)^9 = ( 125 )^ 9/3 so this also same thing
In part C it is ( 12)^2/7) but the ( redical 12 ) ^7 is equal to ( 12)^7/2 so these two are not equivalent
in part D it is 4^1/5 but ( redical 4) ^5 = 4^( 5/2 which is also not equivalent
Answer : only A and B are equivalent
