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Alla [95]
3 years ago
10

For somebody that need it

Mathematics
1 answer:
djverab [1.8K]3 years ago
4 0

Answer:

is there a question in this? lol, if not, tyy!!

Step-by-step explanation:

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You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along
sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}

Then, the time (speed divided by distance) is:

t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1

To optimize this function we have to derive and equal to zero:

\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\  \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\

x

As d_b=x, the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0
3 years ago
Select the correct answer from each drop-down menu.
Annette [7]

All of given options contain quadratic functions. One way to determine the extreme value is squaring the expression with variable x.

Option B contain the expression where you can see perfect square. Thus, equation \bf{y=-(x-2)^2+5} (choice B) reveals its extreme value without needing to be altered.

To determine the extreme value of this equation, you should substitute x=2 (x-value that makes expression in brackets equal to zero) into the function notation:

y=-(2-2)^2+5=5.

The extreme value of this equation has a minimum at the point (2,5).

7 0
2 years ago
Read 2 more answers
3.<br> B<br> ge<br> 18cm<br> A<br> 60°<br> 20cm<br> с<br> Calculate the size of angle ABC.
uysha [10]

Answer:

Step-by-step explanation:

8 0
3 years ago
12a+6b equivalent expression
patriot [66]

Answer:

6(2a+b)

Step-by-step explanation:

The given expression is

12a+6b

To find the equivalent expression of the given one, we just have to factor.

In this case, the only thing we can do to rewrite is to extract the common greatest factor, which is 6

12a+6b\\6(2a+b)

Therefore, the equivalent expression is

6(2a+b)

5 0
3 years ago
What is the 5th term in the arithmetic sequence below?
olga_2 [115]

Answer:

A: 16

Step-by-step explanation:

difference is +12

4 + 12= 16

7 0
3 years ago
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