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vichka [17]
4 years ago
8

Compare and contrast thomsons plum pudding model with rutherfords nuclear atomic model

Chemistry
1 answer:
Aloiza [94]4 years ago
6 0
Rutherford's model did not completely re imagine Thomson's. Like Thomson, Rutherford still believed that atoms contained negatively charged electrons. Unlike the plum pudding model, where those atoms simply floated in "soup," Rutherford believed they orbited the central nucleus just as planets orbit the sun.
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The table shows the amount of radioactive element remaining in a sample over a period of time.
Lunna [17]

Answer:

1. The half-life is 22 years.

2. 132 years

Explanation:

1. Determination of the the half-life.

The half-life of an element is the time taken for half the element to decay.

From the table given above, the original amount of the element 45 g. If we divide 45 by 2, we'll have 22.5 g as half the original amount of element.

Now, the time taken to obtain 22.5 g as shown from the table is 22 years.

Thus, the half-life the element is 22 years.

2. Determination of the time.

Original amount (N₀) = 308 g

Amount remaining (N) = 4.8125 g

Time (t) =?

Next, we shall the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 308 g

Amount remaining (N) = 4.8125 g

Number of half-lives (n) =?

N = 1/2ⁿ × N₀

4.8125 = 1/2ⁿ × 308

Cross multiply

4.8125 × 2ⁿ = 308

Divide both side by 4.8125

2ⁿ = 308 / 4.8125

2ⁿ = 64

Express 64 in index form with 2 as the base.

2ⁿ = 2⁶

n = 6

Thus, 6 half-lives has elapsed.

Finally, we shall determine the time. This can be obtained as follow:

Number of half-lives (n) = 6

Half-life (t½) = 22 years

Time (t) =?

n = t / t½

6= t / 22 years

Cross multiply

t = 6 ×22

t = 132 years.

Thus, the time taken is 132 years.

6 0
3 years ago
The specific heat capacity of aluminum is 0.22 cal/g°C. How much energy needs to flow into 20.0 grams of aluminum to change its
True [87]

Answer:

C)  66 calories

Explanation:

The Heat energy required to flow into a unit mass object to raise its temperature by 1 degree is known as specific heat capacity.

specific heat capacity of aluminum, c = 0.22 cal/g°C

mass of aluminium, m = 20.0 g  

7 0
4 years ago
QY
maria [59]

Answer:

A warm shallow sea.

Explanation:

A warm, shallow sea invaded the Big Bend during the Cretaceous Period, some 135 million years ago, providing the setting for deposition of lime mud and the remains of sea-dwelling organisms such as clams and snails. Limestone layers formed from those shallow muds are now visible throughout much of the Big Bend.

7 0
3 years ago
The distribution of Na+ ions across a typical biological membrane is 10 mmol dm-3 inside the cell and 140 mmol dm-3 outside the
trasher [3.6K]

Answer :  The value of \Delta G^o across the membrane is 6.80 kJ/mol

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln K_{eq}\\\\\Delta G^o=-RT\times \ln (\frac{C_{in}}{C_{out}})

where,

\Delta G^o = standard Gibbs free energy  = ?

R = gas constant = 8.314 J/K.mol

T = temperature = 37^oC=273+37=310K

K_{eq}  = equilibrium constant

C_{in} = concentration inside the cell = 10mmol.dm^{3-}

C_{out} = concentration outside the cell = 140mmol.dm^{3-}

Now put all the given values in the above formula, we get:

\Delta G^o=-RT\times \ln (\frac{C_{in}}{C_{out}})

\Delta G^o=-(8.314J/K.mol)\times (310K)\times \ln (\frac{10mmol.dm^{3-}}{140mmol.dm^{3-}})

\Delta G^o=6.80\times 10^{3}J/mol=6.80kJ/mol

Thus, the value of \Delta G^o across the membrane is 6.80 kJ/mol

8 0
3 years ago
What is an unknown element´s that has 35 protons
Zolol [24]

Solved: An Unknown Element Contains 35 Protons, 36 Electro... | ...

5 0
4 years ago
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