Find the difference in the y-coordinates: -3 - 1 = -4
Find the difference in the x-coordinates in the same order: 2 - 5 = -3
Divide the difference in y by the difference in x: slope = (-4)/(-3)
Reduce the fraction: slope = 4/3
X = 4 y = 3 4x-3y=7 x=13-3y
4(13-3y) -3y =7
52 -12y -3y =7
-15y=-45
-y=-3 y = 3
x=13-(3*3)
x=13-9
x =4
Rearrange to standard form:-
x^2 - 10x + y^2 = 11
(x - 5)^2 - 25 + y^2 = 11
(x - 5)^2 + y^2 = 36
Center of circle = (5, 0) and radius = sqrt36 = 6
No. when plugging 4 into the equation, 0 is not the final result. instead it is 6.
square root of 2(4)+1 = square root of 9 = 3
3+3 = 6
and 6 is not 0 so x cannot = 4