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2 years ago

PLS HELP WILL MARK BRAINLIEST!

Mathematics

2 answers:

Allisa [31]2 years ago

4 0

Answer:

-41

Step-by-step explanation:

if you plug -2 everywhere you see an x and 1 everywhere you see a y, and then simplify you get -41

Alik [6]2 years ago

4 0

⚘Refer to the attachment!!

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What is twelve more than the quotient of 64 and 8? (put in standard form)

pantera1 [17]

Answer:

Step-by-step explanation:

64/8=8

8+12=20

7 0

3 years ago

Please Find x 5x+7=7x-9

irga5000 [103]

Answer: x=8

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

a cylindrical-shaped water storage tank with diameter 60 ft and height 20 ft needs to be painted on the outside. if the tank is

KonstantinChe [14]

Answer:

6600ft.² is the correct answer.

Step-by-step explanation:

Given that,

Diameter of the Cylindrical tank, d = 60 ft
Height of the Cylindrical tank, h = 20 ft
Radius of the Cylindrical tank, r = 30ft.

$\:$

To Find:

Area of the Cylindrical tank to be painted.

$\:$

Solution:

Area of Cylindrical tank to be painted = CSA of the Cylindrical tank + Area of the circle

$\star \quad{ \boxed{ \green{CSA_{(Cylinder)} = 2 \pi r h }}} \quad \star$

$\star \quad{ \boxed{ \green{Area_{(Circle)} = \pi {r}^{2} }}} \quad \star$

$\longrightarrow \: 2\pi rh \: + \pi {r}^{2}$

$\longrightarrow \: \pi r(2h + r)$

$\longrightarrow \: \frac{22}{7} \times 30 \times(2\times20+30)$

$\longrightarrow \: \frac{660}{7} \times (40 + 30)$

$\longrightarrow \: \frac{660}{7} \times 70$

$\longrightarrow \: 660 \times 10$

$\longrightarrow \: 6600 {ft.}^{2}$

Hence, Area of the Cylindrical tank to be painted is 6600ft.²

<h2>_____________________</h2><h3>Additional Information: </h3>

$\footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{ \red{More \: Formulae}}} \\ \\ \bigstar \: \bf{CSA_{(cylinder)} = 2\pi \: rh}\\ \\ \bigstar \: \bf{Volume_{(cylinder)} = \pi {r}^{2} h}\\ \\ \bigstar \: \bf{TSA_{(cylinder)} = 2\pi \: r(r + h)}\\ \\ \bigstar \: \bf{CSA_{(cone)} = \pi \: r \: l}\\ \\ \bigstar \: \bf{TSA_{(cone)} = \pi \: r \: (l + r)}\\ \\ \bigstar \: \bf{Volume_{(sphere)} = \dfrac{4}{3}\pi {r}^{3} }\\ \\ \bigstar \: \bf{Volume_{(cube)} = {(side)}^{3} }\\ \\ \bigstar \: \bf{CSA_{(cube)} = 4 {(side)}^{2} }\\ \\ \bigstar \: \bf{TSA_{(cube)} = 6 {(side)}^{2} }\\ \\ \bigstar \: \bf{Volume_{(cuboid)} = lbh}\\ \\ \bigstar \: \bf{CSA_{(cuboid)} = 2(l + b)h}\\ \\ \bigstar \: \bf{TSA_{(cuboid)} = 2(lb +bh+hl )}\\ \: \end{array} }}$

4 0

2 years ago

Write a rule for the nth term of the geometric sequence: a3=54, a6=1458

Shalnov [3]

Answer:

tn = -1350 + 468n

Step-by-step explanation:

First, we need to find the difference.

1458 - 54 / 6 - 3

= 468

Now we need to find the first term.

t3 = t1 + (n - 1) (d)

54 = t1 + (3 - 1)(468)

54 = t1 + (2)(468)

54 = t1 + 936

-882 = t1

The rule is:

tn = -882 + (n-1) (468)

tn = -882 + 468n - 468

tn = -1350 + 468n

3 0

3 years ago

stack X B with rightwards arrow on top bisects ∠AXC. If m∠AXB = 2x + 10, m∠BXC = 2x + 10, and the m∠AXC = 6x – 6, find the value

Sever21 [200]

Answer:

x=13

Step-by-step explanation:

set up the equation:

AXB+BXC=AXC

(2x+10)+(2x+10)=(6x-6)

calculate for x

x=13

5 0

2 years ago