Answer:
11th revision
Step-by-step explanation:
The first revision is in 2018, and for each 3 years there is a new revision.
From 2018 to 2048, there are 30 years.
So to find how many revisions there are, we can divide the 30 years by the period of 3 years:
Number of revisions = total period / period per revision = 30 / 3 = 10 revisions.
As the year 2018 also has a revision, we have 10 + 1 = 11 total revisions.
So in 2048 there will be the 11th revision.
The answer to your question is 0.
Answer:
(50+40x) dollars
Step-by-step explanation:
THe fixed cost is $50 (this includes everything and 6GB of data).
Now, for every GB <em>OVER</em> 6 GB he uses, company charges $40 extra.
So, if he used "x" GB EXTRA, his EXTRA cost will be 40 * x = 40x
Thus, his total cost in the month would be fixed cost PLUS the extra, which would be
50 + 40x dollars
Answer:
C = 1.
Step-by-step explanation:
x^2 - 2x = (x - 1)^2 - 1 so:
x^2 - 2x + C = (x - 1)^2 - 1 + C
So to get a perfect square C must be 1 ( as -1 + 1 = 0):-
(x - 1)^2 - 1 + 1 = (x - 1)^2
Checking this:
x^2 - 2x + 1
= (x - 1)(x - 1) which is a perfect square./
Answer:

Step-by-step explanation:
Given



Required
Determine the probability of selecting two fakes
The probability can be represented as thus: 
Using the following probability formula, we have:

Each probability is calculated by dividing number of fakes by total number of gems:

The minus 1 (-1) represent the numbers of fake and total gems left after the first selection




<em>Hence, the required probability is approximately 0.504</em>