The answer is B.) benzaldehyde sorry if I’m wrong
Write balanced molecular, ionic, and net ionic equations<span> (NIE) for each of the ... </span>3.Mg(OH)2(aq) +. 2HCl(aq). →. MgCl2(aq). +. 2H2O(l). Ionic Equation: Mg2+(aq). + ... 2-(aq). +. Ca2+(aq). →. Ca(C2O4)(s). 5. 2(NH4)3PO4(aq) +. 3Zn(NO3)2(aq) → ... 2-(aq<span>). →. MgCrO4(s). 9. </span>2FeCl3(aq<span>). +. </span>3Mg<span>(s). →. </span>3MgCl2(aq<span>) +. </span>2Fe<span>(s).</span>
Answer;
K+ and NO3- ions
Explanation;
The main ions remaining are K+ and NO3- ions after pbi2 precipitation is complete.
However; There will always be tiny amounts of Pb2+ and I- ions, but most of them are in the solid precipitate.
The relative abundance and the mass number usually they give these to you. They give me both these values in my chemistry class so i just multiply add the products and get my answer
Answer is 355 grams.
Explanation:
Given the molecular weights:
M
r
N
a
O
H
=
40
g
m
o
l
M
r
N
a
2
S
O
4
=
142
g
m
o
l
The analogy of the moles will be held constant:
n
N
a
O
H
n
N
a
2
S
O
4
=
2
1
n
N
a
O
H
n
N
a
2
S
O
4
=
2
For each one, substitute:
n
=
m
M
r
Therefore:
n
N
a
O
H
n
N
a
2
S
O
4
=
2
m
N
a
O
H
M
r
N
a
O
H
m
N
a
2
S
O
4
M
r
N
a
2
S
O
4
=
2
200
40
x
142
=
2
200
⋅
142
40
x
=
2
200
⋅
142
=
2
⋅
40
x
x
=
200
⋅
142
2
⋅
40
=
100
⋅
142
40
=
10
⋅
142
4
=
1420
4
=
=
710
2
=
355
g
r
a
m
s
(or just use a calculator)
