The volume of gas that exerts a pressure of 457 mmhg if exerted a pressure of 2.50 atm when its volume was 25.0ml is calculated as follows
by use of Bolyes law formula that is P1V1=P2V2
P1= 457mmhg
V1=?
P1 = 2.50 atm = 2.50 x760 = 1900mmhg
V2= 25,0 ml
V1 from the formula above = P2V2/P1
= 1900mm hg x25 ml/ 457 mm hg = 104 ml
Answer:
Eliminate the hazard. ...
Substitute the hazard with a lesser risk. ...
Isolate the hazard. ...
Use engineering controls. ...
Use administrative controls. ...
Use personal protective equipment.
Explanation:
hehe
A. The box will move to the right
The electron bit would be 2 and you could colour in 4 boxes:) I had the same question as this and I got it correct
(a) Reaction of nitric acid with non-metal:
C+4HNO
3
⟶CO
2
+2H
2
O+4NO
2
S+6HNO
3
⟶H
2
SO
4
+2H
2
O+6NO
2
(b) Nitric acid showing acidic character:
K
2
O+2HNO
3
⟶2KNO
3
+H
2
O
ZnO+2HNO
3
⟶Zn(NO
3
)
2
+H
2
O
(c) Nitric acid acting as oxidizing agent
P
4
+20HNO
3
⟶4H
3
PO
4
+4H
2
O+20NO
2
3Zn+8HNO
3
⟶3Zn(NO
3
)
2
+4H
2
O+2NO
hope that helps you please mark brainliest