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3 years ago

5

I need help with this table if anyone can help me it would be my blessing to you and could you maybe show me how to do it?

1 answer:

dusya [7]3 years ago

6 0

This is a hard one bro

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a warehouse holds 460 boxes. They ship out 65 boxes each week. After how many weeks will the warehouse have less than 100 boxes

Kamila [148]

It should take 6 weeks until the warehouse has less than 100 boxes remaining

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2 years ago

Read 2 more answers

Help please, not sure how to do this...

olga nikolaevna [1]

Answer:

8.38

Step-by-step explanation:

The underlined number is in the hundredths place, so that means that we're going to round there. That means that you look at the number to its right and if it's lower than 5, it stays the same. However, if it's 5 or higher, you round it up. For example, if the number was 8.386, we would round it to 8.39.

5 0

3 years ago

Solve the following system of equations algebraically:

d1i1m1o1n [39]

Answer:

(2,1) , (-4,-17)

x = 2 , y = 1

x = − 4 , y = − 17

5 0

3 years ago

PLZ HELP BRAINLIEST

Montano1993 [528]

Answer:

see explanation below

Step-by-step explanation:

You have three pairs of shoes (white, brown, and black), and you have 6 pairs of pants ( brown, blue, grey, white, sand, and black)

We use the Fundamental Counting Principle to find the number of possible pant-shoe combinations:

3 * 6 = 18

then we can find the probability of wearing by random selection brown shoes with either blue or grey pants:

prob (brown shoes & blue pants) + prob (brown shoes & grey pants) =

= 1/18 + 1/18 = 2/18 = 1/9

3 0

3 years ago

At a carnival, 700 tickets were sold for a total

Diano4ka-milaya [45]

Answer:

The adult tickets are <u>400</u> and the children tickets are <u>300</u>.

Step-by-step explanation:

Given:

At a carnival, 700 tickets were sold for a total amount of $5500. An adult ticket cost $10 and a children's ticket cost $5.

Now, to find the number of adult tickets and the number of children's tickets sold.

<em>Let the number of adult tickets be </em> $x.$ <em />

<em>And let the number of children tickets be </em> $y.$ <em />

So, the total number of tickets sold:

$x+y=700\\\\y=700-x\ \ \ ....(1)$

Now, the total amount of tickets:

$x(10)+y(5)=5500$

Substituting the value of $y$ from equation (1):

$x(10)+(700-x)(5)=5500\\\\10x+3500-5x=5500\\\\5x+3500=5500$

<em>Subtracting both sides by 3500 we get:</em>

<em /> $5x=2000$ <em />

<em>Dividing boths sides by 5 we get:</em>

$x=400.$ <u />

<u>The number of adult tickets = 400.</u>

Now, substituting the value of $x$ in equation (1) we get:

$y=700-x\\\\y=700-400\\\\y=300.$

<u>The number of children tickets = 300.</u>

Therefore, the adult tickets are 400 and the children tickets are 300.

8 0

3 years ago