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ycow [4]
3 years ago
9

3- Fully folded proteins typically have polar side chains on their surfaces, where electrostatic attractions and hydrogen bonds

can form between the polar group on the amino acid and the polar molecules in the solvent. In contrast, some proteins have a polar side chain in their hydrophobic interior. Which of the following would not occur to help accommodate an internal, polar side chain?
a) A hydrogen bond forms between two polar side chains.b) A hydrogen bond forms between a polar side chain and protein backbone.c) A hydrogen bond forms between a polar side chain and a hydrophobic side chain.d) Hydrogen bonds form between polar side chains and a buried water molecule.
Chemistry
1 answer:
Elden [556K]3 years ago
5 0

Answer:

Option C= A hydrogen bond formed between a polar side chain and a hydrophobic side chain.

Explanation:

All three given options a, b and d have common mechanism to accommodate the polar amino acid.

A= A hydrogen bond forms between two polar side chains.

B= A hydrogen bond from between a polar side chain and protein back bone.

D =  hydrogen bond form between polar side chains and a buried water molecules.

All these are use to accommodate the polar amino acid.

While option C is not used. which is:

A hydrogen bond formed between a polar side chain and a hydrophobic side chain.

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matrenka [14]
Image C is adhesion stronger and Image D is cohesion stronger
5 0
3 years ago
Consider the following reaction at equilibrium. What effect will increasing the pressure of the reaction mixture have on the sys
8090 [49]

Answer:

Choice d. No effect will be observed as long as other factors (temperature, in particular) are unchanged.

Explanation:

The equilibrium constant of a reaction does not depend on the pressure. For this particular reaction, the equilibrium quotient is:

Q = \displaystyle \frac{[\mathrm{SO_2\, (g)}]}{[\mathrm{O_2\, (g)}]}.

Note that the two sides of this balanced equation contain an equal number of gaseous particles. Indeed, both [\mathrm{SO_2\, (g)}] and [\mathrm{O_2\, (g)}] will increase if the pressure is increased through compression. However, because \rm SO_2\, (g) and \rm O_2\, (g) have the same coefficients in the equation, their concentrations are raised to the same power in the equilibrium quotient Q.

As a result, the increase in pressure will have no impact on the value of Q\!. If the system was already at equilibrium, it will continue to be at an equilibrium even after the change to its pressure. Therefore, no overall effect on the equilibrium position should be visible.

8 0
3 years ago
Can anyone help explain how to convert moles to grams and grams to moles im completely lost
Pepsi [2]
Simple dimensional analysis.

okay so youll need a periodic table to look up the molar mass. youll be given either an amount of grams or moles.

7 0
3 years ago
A liquid occupies a volume of 5.0 L has a mass of 6.0 kg. what is the density of a the lights in kg/L
grandymaker [24]

Answer:

Hey there! :

Volume = 5.0 L

mass = 6.0 Kg

Therefore:

Density = mass / Volume

Density = 6.0 / 5.0

Density = 1.2 kg/L

6 0
3 years ago
5. A gas has a pressure of 1.26 atm and occupies a volume of 7.40 L. If the gas
marin [14]

Answer:

0.499atm

Explanation:

The formula is

P1/V1 = P2/V2

so:

1.26atm/7.40L = P2/2.93L

then:

(1.26atm/7.40L)*2.93L = P2

= 0.4988918911atm

the answer must have 3 sig figs

8 0
3 years ago
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