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2 years ago

Use the drop-down menus to choose the correct answer to complete each statement.

Chemistry

2 answers:

Yakvenalex [24]2 years ago

6 0

Answer:

moon, planet, planet

Explanation:

moons revolve around planets

Jupiter is considered a planet because it revolves the sun

and a planet is a body that revolves a star a dwarf planet doesn't revolve around a star

Alexxandr [17]2 years ago

4 0

Answer:

THIS IS WRONG 0.0

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Explanation:

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Balance the equation by inserting coefficients as needed. equation: ZnS + HBr -> ZnBr_{2} + H_{2}S ZnS + HBr ⟶ ZnBr 2 + H 2 S

yawa3891 [41]

Answer : The balanced chemical reaction will be,

$ZnS+2HBr\rightarrow ZnBr_2+H_2S$

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

If the amount of atoms of each type on the left and right sides of a reaction differs then to balance the equation by adding coefficient in the front of the elements or molecule or compound in the chemical equation.

The coefficient tell us about that how many molecules or atoms present in the chemical equation.

The given chemical reaction is,

$ZnS+HBr\rightarrow ZnBr_2+H_2S$

This reaction is an unbalanced chemical reaction because in this reaction number of hydrogen bromine atoms are not balanced.

In order to balance the chemical equation, the coefficient '2' put before the $HBr$ and we get the balanced chemical equation.

The balanced chemical reaction will be,

$ZnS+2HBr\rightarrow ZnBr_2+H_2S$

8 0

3 years ago

Identify two sources of heat that melt rocks beneath Earth's surface.

elena55 [62]

Answer:

magma, melting

8 0

2 years ago

enzyme‑catalyzed, single‑substrate reaction E + S − ⇀ ↽ − ES ⟶ E + P . The model can be more readily understood when comparing t

laila [671]

Complete Question

The complete question is shown on the first uploaded image

Answer:

[S]<<KM | [S]=KM | [S]>>KM | Not true

____________ | Half of the active | Reaction rate is | Increasing

$[E_{free}]$ is about | sites are filled of | independent of | $[E_{Total}]$ will

equal to $[E_{total}]$ . | | [S] | lower KM

_____________________________________________|____________

[ES] is much | | Almost all active

lower than | | sites are filled

$[E_{free}]$ | |

Explanation:

Generally the combined enzyme $[ES]$ is mathematically represented as

$[ES] = \frac{[E_{total}][S]}{K_M + [S]}----(1)$

for Michaelis-Menten equation

Where $[S]$ is the substrate concentration and $K_M$ is the Michaelis constant

Considering the statement $[S] < < K_M$

Looking at the equation $[S]$ is denominator so it can be ignored(it is far too small compared to $K_M$ ) hence the above equation becomes

$[ES] = \frac{[E_{total}][S]}{K_M}$

Since $[S]$ is less than $K_M$ it means that $\frac{[S]}{K_M} < < 1$

so it means that $[ES] < < [E_{total}]$

What this means is that the number of combined enzymes $[ES]$ i.e the number of occupied site is very small compared to the the total sites $[E_{total}]$ i.e the total enzymes concentration which means that the free sites [ $E_{free}]$ i.e the concentration of free enzymes is almost equal to $[E_{total}]$

Considering the second statement

$[S] = K_M$

So this means that equation one would now become

$[ES] = \frac{[E_{total}][S]}{2[S]} = \frac{[E_{total}]}{2}$

So this means that half of the active sites that is the total enzyme concentration are filled with S

Considering the Third Statement

$[S] >>K_M$

In this case the $K_M$ in the denominator of equation 1 would be neglected and the equation becomes

$[ES] = \frac{[E_{total}] [S]}{[S]} = [E_{total}]$

This means that almost all the sites are occupied with substrate

The rate of this reaction is mathematically defined as

$v =\frac{V_{max}[S]}{K_M [S]}$

Where v is the rate of the reaction(also know as the velocity of the reaction at a given time t) and $V_{max}$ is he maximum velocity of the reaction

In this case also the $K_M$ at the denominator would be neglected as a result of the statement hence the equation becomes

$v = \frac{V_{max}[S]}{[S]} = V_{max}$

So it means that the reaction does not depend on the concentration of substrate [S]

For the final statement(Not True ) it would match with condition that states that increasing $[E_{total}]$ will lower $K_M$

This is because $K_M$ does not depend on enzyme concentration it is a property of a enzyme

7 0

2 years ago

A star is mainly made of hydrogen gas, but most classes of stars include other elements such as helium, calcium, and other heavi

Xelga [282]

That would be true, since most other stats include helium, calcium, etc

6 0

2 years ago

Read 2 more answers

Cl2 + 2OH− → Cl− + ClO− + H2O

Nataly_w [17]

Cl2(g) -------> Cl-(aq) + ClO-(aq)

2e- + Cl2(g) -------> 2Cl-(aq) [reduction]

4OH-(aq) + Cl2(g) -----------> 2ClO-(aq) + 2H2O(l) + 2e- [oxidation]
______________________________________...
2OH-(aq) + Cl2(g) --------> Cl-(aq) + ClO-(aq) + H2O(l)

4 0

3 years ago