Answer:
Step-by-step explanation:
I'll draw a quick sketch. It's hard to "see" this kinda of problem w/o a drawing , so start there. just draw as much as you can from what the problem tells you.
diameter = 14 cm
radius = 7 cm
pi = 3.142
PRQ = 35 °
to find Y use law of sines
sin(70) / Y = sin(55) / 7
sin(70) / sin(55) / 7 = Y ( I'll use my calculator for all the non standard angles )
sin(70) * 7 / sin(55) = Y ( and invert and multiply the fraction in the denom )
8.03007 = Y
x = 70 °
if you have questions, and you should, just put them in the comments , I'll see them later :)
Answer:
343.7 ft
Step-by-step explanation:
The wire is anchored 190 -13 = 177 ft from the ground. That distance is opposite the given angle (31°). The measure you want is the hypotenuse of the triangle with that side and angle measures.
The mnemonic SOH CAH TOA reminds you that the relation between the opposite side, hypotenuse, and angle is ...
Sin(angle) = Opposite/Hypotenuse
Filling in the given information, you have ...
sin(31°) = (177 ft)/hypotenuse
Solving for hypotenuse gives
hypotenuse = (177 ft)/sin(31°) ≈ 343.7 ft
The length of the guy wire should be 343.7 ft.
Answer:
Question 1:
a. The answer is B because the graph inclined really quickly and then it inclined at a much slower pace, suggesting that the person was running and then walking.
b. The answer is C because you can see on the graph that after a while, the distance from the starting point goes back to 0, indicating that the person forgot something at home.
Question 2:
a. The dashed line reaches the bottom at 15:30 so the answer is C.
b. Siobhan travels 8 km to go from home to school so the answer is 2 * 8 = 16 which is option D.
Question 3:
The answer is C because after the distance from the starting point increased, it then decreased and came back to the original point suggesting that he walked, turned around and walked back to the starting point.
To solve the problem we must know the basic exponential properties.
<h3>What are the basic exponent properties?</h3>
![\sqrt[m]{a^n} = a^{\frac{n}{m}}](https://tex.z-dn.net/?f=%5Csqrt%5Bm%5D%7Ba%5En%7D%20%3D%20a%5E%7B%5Cfrac%7Bn%7D%7Bm%7D%7D)
The expression can be written as ![x^9\sqrt[3]{y}](https://tex.z-dn.net/?f=x%5E9%5Csqrt%5B3%5D%7By%7D)
.
Given to us
Using the exponential property,
Using the exponential property ,
![=x^9\times y^\frac{1}{3}\\\\=x^9\times \sqrt[3]{y}\\\\=x^9 \sqrt[3]{y}](https://tex.z-dn.net/?f=%3Dx%5E9%5Ctimes%20y%5E%5Cfrac%7B1%7D%7B3%7D%5C%5C%5C%5C%3Dx%5E9%5Ctimes%20%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C%3Dx%5E9%20%5Csqrt%5B3%5D%7By%7D)
Hence, the expression can be written as .
Learn more about Exponent properties:
brainly.com/question/1807508
