I need help with this word problem this is new to me and I really need help can you please help me?

Mathematics

2 answers:

Arisa [49]3 years ago

8 0

4 subs because 12 divided by 3 equals 12

adelina 88 [10]3 years ago

4 0

Divide 12 by 3 and u get four so you need four long sandwich's to make 12 small ones

You might be interested in

60 is 25% of what number?

Marysya12 [62]

Your answer would be 15. You first would move the "pretend" decimal to the left 2 times. so it would end up being 0.25. So then you would set up your problem. 0.25 x 60 =. Which should give you the answer of 15.

5 0

3 years ago

Read 2 more answers

A hockey player hits a puck along the ice, giving it an initial speed of 2.9 meters per second. If there is no friction between

Alborosie

2.9 × 1.7 = 4.93

After 1.7 seconds, the puck's speed would be 4.93 meters per second.

5 0

3 years ago

There are 12 inches in a foot. Find the number of inches in 6 feet

Scrat [10]

Answer:

72 inches

Step-by-step explanation:

12 × 6 = 72

Answer: There are 72 inches in 6 feet

3 0

3 years ago

Read 2 more answers

There are going to be presentations at a school. If 30 people can fit in a room, how many rooms are necessary if there area tota

DanielleElmas [232]

Hello again lol. I would think it would be two rooms don’t count me on this one but I think it is two

7 0

3 years ago

Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6

horsena [70]

Answer:

$x^{4} -18x^{3}+104x^{2} -172x-100$

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:

$\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))( x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\$

7 0

3 years ago