Inquiry; wanting to know. Thinking critically to figure out, understand. However being skeptic to not fall on one simple answer. For possibly, it could be incorrect.
<span> Because it is diprotic acid, we can write like R(COOH)2 ( it can be written as H2A also)
</span>R(COOH)2+2NaOH ----> R(COONa)2+2H2O
<span>25.0 ml of a 0.100 m NaOH solution
25.0 ml=0.0250 L solution Of NaOH
</span> 0.100 m NaOH=0.100 mol/L
0.0250 L *0.100 mol/L=0.00250 mol NaOH
0.00250 mol NaOH*1mol R(COOH)2/2 mol NaOH=0.00125 mol acid
0.00125 mol R(COOH)2*118g R(COOH)2/1mol R(COOH)2 = 0.148 g acid
Answer is 0.148 g <span>Succinic acid</span>
I think the answer is true
Answer:
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Answer:
CHCl₃
Explanation:
We have the following data:
C = 5.03 g
H = 0.42 g
Cl= 44.5 g
First, we divide each mass by the molar mass (MM) of the chemical element to calculate the moles:
MM(C) = 12 g/mol
moles of C = mass/MM(C) = 5.03 g/(12 g/mol) = 0.42 mol C
MM(H) = 1 g/mol
moles of H = mass/MM(H) = 0.42 g/(1 g/mol) = 0.42 mol H
MM(Cl) = 35.4 g/mol
moles of Cl = mass/MM(Cl) = 44.5 g/(35.4 g/mol) = 1.26 mol Cl
Now, we divide the moles by the smallest number of moles (0.42):
0.42 mol C/0.42 = 1 C
0.42 mol H/0.42 = 1 H
1.26 mol Cl/0.42 = 3 Cl
Thus, the C:H:Cl ratio is 1:1:3.
Therefore, the empirical formula is CHCl₃