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4 years ago

How do i know which equation to use for dimensional analysis?

1 answer:

7 0

You look at the units you want, then try to figure out which units ti multiply by to get the units you have to match the units you want. For example, if you want kg/m^3 and have m/s

You can see that you have a length/time(lets denote it d/t for distance over time) and want mass/volume (lets denote it m/d^3). d/t multiplied by time=d but we want m/d^3 so lets multiply our original d/t by time(t) and mass(m) so d/t(t) (m) =dm. However, we want m/d^3 so we will also have to divide by d^4.

(d/t)(t)(m) /(d^4)=m/d^3 = mass/length^3 =mass/volume which was what we wanted our end result to be.

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The solar system is made up of eight planets, numerous comets, asteroids and moons, and the Sun. The force that holds all of the

s2008m [1.1K]

Your answer is Gravity

Hope this could help :)

5 0

3 years ago

Question 1 of 10

Marianna [84]

Answer:

Option D. ²²²₉₀Th

Explanation:

Let the unknown be ⁿₘZ. Thus, the equation becomes:

²²⁶₉₂U —> ⁴₂He + ⁿₘZ

Next, we shall determine n, m and Z. This can be obtained as follow:

For n:

226 = 4 + n

Collect like terms

226 – 4 = n

222 = n

n = 222

For m:

92 = 2 + m

Collect like terms

92 – 2 = m

90 = m

m = 90

For Z:

ⁿₘZ => ²²²₉₀Z => ²²²₉₀Th

Therefore, the complete equation becomes:

²²⁶₉₂U —> ⁴₂He + ⁿₘZ

²²⁶₉₂U —> ⁴₂He + ²²²₉₀Th

Thus, the unknown is ²²²₉₀Th

6 0

3 years ago

A 1425 kg car located at < 266, 0, 0 > m has a momentum of < 46000, 0, 0 > kg·m/s. What is its location 11 s later?

True [87]

Answer:

<621, 0 , 0>

Explanation:

given,

mass of the car ,m = 1425 Kg

location of car = < 266, 0, 0 > m

momentum of the car = < 46000, 0, 0 > kg.m/s

M v_x = 46000

1425 x v_x = 46000

v_x = 32.28 m/s

v_y = 0 m/s

v_z = 0 m/s

Location of the car after 11 s

x = v_x t + 266

x = 32.28 x 11 + 266

x = 621 m

hence, the location of car after 11 s is equal to <621, 0 , 0>

4 0

3 years ago

A charged particle is located in an electric field where the magnitude of the electric field strength is 2.0x10^3 newtons per co

Alexxandr [17]

Answer:

20.7

Explanation:

:0 because basis of the daily occured

6 0

3 years ago

You are hiking in the mountains and find a shiny gold nugget. It might be the element gold, or it might be "fool's gold ," which

ra1l [238]

Answer:

The answer is: letter c, density.

Explanation:

Gold is a chemical element that is <em>very rare.</em> It has a high atomic number and is represented by the symbol "Au."

The problem above is asking about the physical property of gold that will help you determine whether a shiny gold nugget is, indeed, real gold. Remember that you are hiking and not anywhere else in the world.

If you look at choice a, appearance. This is definitely incorrect because looking at the object will not be able to help you verify whether it is true gold or "fool's gold." Considering melting point (letter b) would also be hard because you will be needing the necessary equipment to melt gold. Gold melts at 1,064 degrees Celsius. So,this sounds very impractical. (thus, melting point is incorrect) Now, if you look at letter d, physical state, it goes the same way with appearance. It will only tell you that the object is solid and that's it.

Letter c, density is the answer because if you analyze the density of gold, which is 19.32 grams per cubic meter, it is far from the density of iron pyrite (fool's gold) which is 4.8-5 grams per cubic meter. This means that gold is denser or heavier than iron pyrite. You will definitely be able to tell which such big gap in their densities.

6 0

3 years ago