Answer:
The linesegment 2 to 3.
Explanation:
Becuase time goes on increasing but distance is constant.
Answer:
The left train travels 2378 m until it reaches the meeting point.
Explanation:
The equation for the position of the trains is the following:
x = x0 + v · t
Where:
x = position at time t
x0 = initial position
v = velocity
t = time
If we place the origin of the frame of reference at the initial position of the left train, the right train will be at an initial position of 4744. 6 m relative to the left train. The velocity of the right train will be negative because it will be heading towards the origin.
At the meeting point, the position of both trains is the same:
x left train = x right train
x0₁ + v₁ ·t = x0₂ + v₂ · t
0m + 29 m/s · t = 4744.6 m - 29 m/s · t
58 m/s · t = 4744.6 m
t = 4744.6 m / 58 /s
t = 82 s
The position of the left train at that time will be:
x = x0 + v · t
x = 0 m + 29 m/s · 82 s
x = 2378 m
The left train travels 2378 m until it reaches the meeting point.
The x-component is related with the Force through the trigonometric function cosine.
cos(42°) = x-component / F ⇒ x-component = Fcos(42°) = 112N*0.743 = 83.2 N
<span>The distance between two objects is increased by three times the oringinal distance. Since they were already separated by one time the original distance,
the additional three times the oringinal distance now puts them four times the original distance apart.
Whether we're talking about the gravitational forces of attraction or
the electrical forces of attraction, either one is inversely proportional
to the square of the distance between the objects.
So changing the distance to four times the original distance causes
the forces to become 1/4</span>² as strong as they were originally.
The forces become 1/16 of their original magnitude.<span>
</span>
Answer:
I know someone anwsered but it would be 400M
Explanation:
i initial velocity (u)=10m/s
acceleration (a)=0
time taken (t) =40s
then distance (s)=u t +1/2 a t^2
s= u t +0 (as a is 0)
s= 10 x 40
s= 400M
