Question

an object at rest starts accelerating if it travels 30 meters to end up going 10 m/s what was it’s acceleration

Answer 1

First we have to calculate the time taken to travel the distance 30 m, is

$t = \frac{distance}{velocity} = \frac{30 \ m}{10 \ m/s } = 3 \ s$.

Now from equation of motion,

$v = u + at$

Given, $v = 10 \ m/s$ .

As object starts from rest, so  u = 0.

Substituting these values in above equation, we get

 $10 \ m/s = 0 + a \times 3 \ s \\\\ a = \frac{10}{3} = 3.33 \ m/s^2$.

Thus, the acceleration is $3.33 \ m/s^2$