Answer:
Height as seen by the professor = 38.2 m
Explanation:
Angle of throw = θ = 69°
Velocity of throw = v
X component of velocity = v₁ = v cos 69 = 0.3584 v m/s
Vertical component of the velocity = v₂ = v sin 69 = 0.9336 v m/s
v₂ / v₁ = tan 69 = 2.605
v₂ = 2.605 v₁.
Professor sees as if the x component of velocity =0
v (as seen by professor) + v' = 0
=> v as seen by professor = -v' = -10.5 m/s
This shows that y component of the ball's velocity is 2.605 times its x component of velocity.
with respect to the professor, there is only y component of velocity.
v₂' =v₂ = 2.605 ( -10.5) = 27.4 m/s.
Height as seen by the professor = (27.4)² / 2(9.8) = 38.2 m
After thorough researching, the net gravitational force Fnet acting on the earth in the sun-earth-moon system during the new moon and when the moon is located directly between the earth and the sun is 3.50x10^22 N. The correct answer to the following given statement above is 3.50x10^22 N.
Answer:
cerro azul
Explanation:
I reverse image searched and it popped up with a name.
<span>a. bends away from the normal</span>
