Question

What is the equation of this line in standard form?

Answer 1

Option B 6x-7y = -11 is correct

Step-by-step explanation:

We need to write the equation of the given line in standard form.

The points are (1/2,2) and (3,1)

The equation used is:

$y-y_{1}=m(x-x_{1})$

where m is the slope.

Finding slope :

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

x₁= 1/2, y₁=2, x₂=-3, y₂=-1

Putting values:

$m=\frac{-1-2}{-3-1/2} \\m=\frac{6}{7}$

Now taking point (1/2,2) and s;ope m = 6/7 finding equation:

$y-y_{1}=m(x-x_{1})$

$y-2=\frac{6}{7}(x-\frac{1}{2})\\ 7(y-2)=6(x-\frac{1}{2})\\7y-14=6x-3\\7y-6x=-3+14\\7y-6x= 11\\Multiply \,\,with\,\, -1\\-7y+6x=-11\\6x-7y=-11$

So, Option B 6x-7y=-11 is correct

Keywords: Standard form of equation

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