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lorasvet [3.4K]
3 years ago
6

What is the equation of this line in standard form?

Mathematics
1 answer:
horsena [70]3 years ago
5 0

Option B 6x-7y = -11 is correct

Step-by-step explanation:

We need to write the equation of the given line in standard form.

The points are (1/2,2) and (3,1)

The equation used is:

y-y_{1}=m(x-x_{1})

where m is the slope.

Finding slope :

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

x₁= 1/2, y₁=2, x₂=-3, y₂=-1

Putting values:

m=\frac{-1-2}{-3-1/2} \\m=\frac{6}{7}

Now taking point (1/2,2) and s;ope m = 6/7 finding equation:

y-y_{1}=m(x-x_{1})

y-2=\frac{6}{7}(x-\frac{1}{2})\\  7(y-2)=6(x-\frac{1}{2})\\7y-14=6x-3\\7y-6x=-3+14\\7y-6x= 11\\Multiply \,\,with\,\, -1\\-7y+6x=-11\\6x-7y=-11

So, Option B 6x-7y=-11 is correct

Keywords: Standard form of equation

Learn more about Standard form of equation at:

  • brainly.com/question/4097107
  • brainly.com/question/12954015
  • brainly.com/question/1979240

#learnwithBrainly

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The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.​
erma4kov [3.2K]

Answer:

  • CSA of the cylinder = 440 sq. cm

  • Volume of the cylinder = 1540 cu. cm

\\

Step-by-step explanation:

Given:

  • Radius of the cylinder = 7 cm
  • Height of the cylinder = 10 cm

\\

To Find:

  • Curved surface area
  • Volume

\\

Solution:

\\

Using formula:

\dashrightarrow \:  \:  { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA  \: of  \: cylinder = 2\pi rh}}}}}}  \:  \star \\  \\

<em>Substituting the required values: </em>

\\

\dashrightarrow \:  \:  \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times  10 \\  \\  \\  \dashrightarrow \:  \:  \sf CSA {(cylinder)}  = 2 \times 22 \times 10 \\  \\ \\   \dashrightarrow \:  \:  \sf CSA {(cylinder)} = 44 \times 10 \\  \\  \\  \dashrightarrow \:  \:  \sf CSA {(cylinder)}  = 440 \:  {cm}^{2}  \\ \\ \\

Now,

\dashrightarrow \:  \:  { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}=  \pi {r}^{2} h}}}}}}  \:  \star \\  \\ \\

<em>Substituting the required values, </em>

\\

\dashrightarrow \:  \:   \sf Volume {(cylinder)}=  \dfrac{22}{7}  \times  {(7)}^{2}  \times 10 \\ \\  \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}=  \frac{22}{7}  \times 49  \times 10 \\ \\ \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\  \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}= 1540 {cm}^{3}  \\ \\ \\

Hence,

  • CSA of the cylinder = 440 sq. cm

  • Volume of the cylinder = 1540 cu. cm
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