Answer:
A) Distance time graph
B) d(t) = 25t
C) The expression shows the distance more clearly.
Step-by-step explanation:
A) A distance time graph as seen in the attachment provides a representation of the distance travelled.
We are told the car travels at a constant speed of 100 meters per 4 seconds. Which means that 100 m for each 4 hours. So, for 200m, it's 8 hours like seen in the graph and for 300m,it's 12 hours as seen in the graph.
B) And expression for the distance is;
d = vt
Where;
d is distance in metres
v is speed in m/s and t is time
We are told that the car travels at a constant speed of 100 meters per 4 seconds.
Thus, v = 100/4 = 25 m/s
Distance travelled over time is;
d(t) = 25t
C) Looking at both A and B above, it's obvious that the expression of the distance shows a more clearer way of getting the distance because once we know the time travelled, we will just plug it into the equation and get the distance. Whereas, for the representation form, one will need to longer graphs if the time spent is very long.
Answer:
i would say A. The initial cost for renting a snowmobile is $75, with each hour of use costing an additional $25.
Step-by-step explanation:
4/5x - 4/10 = 2/20...multiply everything by common denominator 20
16x - 8 = 2
16x = 2 + 8
16x = 10
x = 10/16 which reduces to 5/8 <=
Continuous compounding is the mathematical limit that compound interest can reach.
It is the limit of the function A(1 + 1/n) ^ n as n approaches infinity. IN theory interest is added to the initial amount A every infinitesimally small instant.
The limit of (1 + 1/n)^n is the number e ( = 2.718281828 to 9 dec places).
Say we invest $1000 at daily compounding at yearly interest of 2 %. After 1 year the $1000 will increase to:-
1000 ( 1 + 0.02/365)^365 = $1020.20
with continuous compounding this will be
1000 * e^1 = $2718.28
Answer:
AB/DE=BC/EF=AC/DF
Step-by-step explanation:
Corresponding segments are designated by letters in corresponding positions in the triangle names. For example, of one segment is designated using the 1st and 2nd letters of one triangle name (such as AB), then the corresponding segment is designated using the 1st and 2nd letters of the other triangle name (such as DE).
Corresponding segments are proportional in length. Corresponding angles are congruent.
