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Phoenix [80]
3 years ago
5

A sample of n = 5 scores has a mean of m = 8. one new score is added to the sample and the new mean is calculated to be m = 9. w

hat is the value of new score?
Mathematics
2 answers:
Yuri [45]3 years ago
6 0
If the 5 scores have a mean of 8, then their total sum would be 8*5 = 40

Now if one score if added (let's call this score x), there are 6 scores and the mean changes to 9, thus:
(40 + x)/6 = 9
40 + x = 54
x = 14
jok3333 [9.3K]3 years ago
3 0
When = n = 5, m = 8 , total = 5 x 8 = 40

When n = 6, m = 9, total = 6 x 5 = 54

The new number = 54 - 40 = 14


Answer: The new value is 14.
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It would be...
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the length of a rectangular garden is 3 m greater than the width. The area of the garden is 70m squared. find the dimensions of
Lerok [7]
A = l x w

so you know that the length is 3m longer than the width, so you could use a formula to represent that

w = l + 3

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you could then rearrange the formula and solve for l using the quadratic formula 

0 = l^2 + 3l - 70

l = -3 +- (square root (3)^2 - 4(1)(70)) / 2(1)
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since a length cannot be negative, this root is not viable. therefore l = 7

to solve for w you would use

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4 0
3 years ago
What multiplies to -12 but added together equals -10
Airida [17]
Let the two numbers be x and y, then,
xy = -12 . . . (1)
x + y = -10 . . . (2)
From (2), x = -10 - y . . . (3)
Putting (3) into (1), gives
(-10 - y)y = -12
-10y - y^2 = -12
y^2 + 10y - 12 = 0
y= \frac{-10\pm \sqrt{10^2-(4\times(-12))} }{2} = \frac{-10\pm \sqrt{148} }{2} = \frac{-10\pm 2\sqrt{37} }{2} = -5\pm\sqrt{37}

Therefore, the two numbers are -5+\sqrt{37} and -5-\sqrt{37}
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It all depends on how big the boxes are but i would say about 5 or 6 boxes if they are big boxes
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