Answer:
59049 digits
Step-by-step explanation:
Given
Digits = 0 to 9
Required
Determine number of 5 digit pins that must not contain 0
There are 10 digits.
Since the pin must not contain 0, there are 9 digits left to select from.
The question didn't state that a digit can not be repeated, so I'll assume that repetition of digit is allowed.
The 1st digit of the 5 could be any of the 9 digits
The 2nd could be any of the 9 digits
The 3rd could be any of the 9 digits
The 4th could be any of the 9 digits
The 5th could be any of the 9 digits
Hence, number of selection is calculated as this:
Selection = 9 * 9 * 9 * 9 * 9
Selection = 59049
Answer:
The answer is D(t) = 160 - 25t
Step-by-step explanation:
well khan academy said it lol
Step-by-step explanation:
In ordee to round the number 7209 to the nearest thousands, we take a look at the digit in the hundreds place (which is 2).
Since 2 < 5, we round the number itself down to the nearest thousands:
7209 => 7000.
Hence our rounded number is 7000.
Answer: it hink its Near integers
Step-by-step explanation:
Answer: 7.29π mm²
Step-by-step explanation:
First, I am assuming XY is the diameter of the circle :)
The formula for the area of a circle is πr² (r = radius)
So that means we need to divide the diameter by 2 to find the radius
5.4 / 2 = 2.7
Now we simply plug in our numbers!
3.14 · 2.7²
3.14 · 7.29
And that's it!
Hope this helped you :)
