Question

Use substitution to solve the system of linear equations. In your final answer, include all of your work.

Answer 1

Answer:

No solutions

Step-by-step explanation:

Substitute $3x-9$ instead of $y$ into the second equation:

$x-\dfrac{1}{3}(3x-9)=-3$

Use distributive property to open the brackets:

$x-\dfrac{1}{3}\cdot 3x+\dfrac{1}{3}\cdot 9=-3\\ \\x-x+3=-3\\ \\3=-3$

This equality is false (3 is not equal to -3), so the system of two equations has no solutions.