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Fudgin [204]
3 years ago
10

3/7 of students at a school are boys. If there are 2282 students at the school, how many are girls?

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
8 0

Answer:

2282 divided by 3over7

enot [183]3 years ago
7 0

Answer:

1304

Step-by-step explanation:

2282:7 =326

326 . 3 = 978

2282 - 978 = 1304

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Consider the numbers √27 and √39.
kobusy [5.1K]
√27 = 5.2 (to 1 dp)
√39 = 6.2 (to 1 dp)
A. √39 is greater.
B. 6 is the only whole number between the two.
Hope this helped :)
3 0
3 years ago
PLEASE HELP .!!! ILL GIVE BRAINLIEST.. *EXRTA POINTS* .. DONT SKIP :(( ! <br> ILL GIVE 40 POINTS .
aksik [14]
To find slope between two given points:
(y2-y1)/(x2-x1)
Find the difference between the first two points
12-9.5/2-1 = 2.5/1 = 2.5
14.5-12/3-2 = 2.5/1 = 2.5
17-14.5/4-3 = 2.5/1 = 2.5
The rate of change between each point is 2.5
7 0
3 years ago
Solve the system of equations algebraically.<br><br> 3x+8y=−6<br> x−y=9 <br> (x,y)= (
vova2212 [387]

Step-by-step explanation:

x=y+9

substitute

3(y+9)+8y=-6

3y+27+8y= -6

13y = -6 -27

13y= -33

y = -33/13

x = -33/13 + 9

4 0
2 years ago
An Internet reaction time test asks subjects to click their mouse button as soon as a light flashes on the screen. The light is
Ganezh [65]

Answer:

(a) 0.20

(b) 31%

(c) 2.52 seconds

Step-by-step explanation:

The random variable <em>Y</em> models the amount of time the subject has to wait for the light to flash.

The density curve represents that of an Uniform distribution with parameters <em>a</em> = 1 and <em>b</em> = 5.

So, Y\sim Unif(1,5)

(a)

The area under the density curve is always 1.

The length is 5 units.

Compute the height as follows:

\text{Area under the density curve}=\text{length}\times \text{height}

                                          1=5\times\text{height}\\\\\text{height}=\frac{1}{5}\\\\\text{height}=0.20

Thus, the height of the density curve is 0.20.

(b)

Compute the value of P (Y > 3.75) as follows:

P(Y>3.75)=\int\limits^{5}_{3.75} {\frac{1}{b-a}} \, dy \\\\=\int\limits^{5}_{3.75} {\frac{1}{5-1}} \, dy\\\\=\frac{1}{4}\times [y]^{5}_{3.75}\\\\=\frac{5-3.75}{4}\\\\=0.3125\\\\\approx 0.31

Thus, the light will flash more than 3.75 seconds after the subject clicks "Start" 31% of the times.

(c)

Compute the 38th percentile as follows:

P(Y

Thus, the 38th percentile is 2.52 seconds.

4 0
3 years ago
Who can help!!! asap​
Ilya [14]

Answer:

0.33= 33/100

<h2>Hope it helps...</h2>
4 0
3 years ago
Read 2 more answers
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