Ask question

Ask question

All categories

3 years ago

10

Two large numbers of the Fibonacci sequence are F49 = 7,778,742,049 and F50 = 12,586,269,025. What is the approximate value of t

he quotient ?

1 answer:

Lina20 [59]3 years ago

4 0

Two large numbers of the Fibonacci sequence are F49<span>= </span>7778742049 and F50=12586269025<span>.</span>

You might be interested in

A circle has a radius of 3. An arc in this circle has a central angle of 20°.

sladkih [1.3K]

360 degrees in 1 circle

the circumference is same ratio

60/360=1/6

1/6 of circumference is the legnth of the arc

radius=3

c=2pir

c=2pi3

c=6pi

1/6 of 6pi is pi

the arc is pi units long

4 0

3 years ago

Read 2 more answers

Which of the following is a relative adverb

siniylev [52]

Answer:

what is the follwing adverb???

ummmmmmmm.....

3 0

3 years ago

Chucky grabbed 11 1111 items in the grocery store that each had a different price and had a mean cost of about $ 4.44 $4.44dolla

maria [59]

Question:

Chucky grabbed 11 items in the grocery store that each had a different price and had a mean cost of about $4.44. On his way to the register, he gave in to an impulse to add a 12th item: an entire wheel of cheese that cost $39.99.

How will adding the wheel of cheese affect the mean and median?

Answer:

There will be a big difference in the mean when the new item is added

Step-by-step explanation:

Given

$Items = 11$

$Mean = \$4.44$

Before we solve further, we need to first calculate the total amount of the 11 items.

$Mean = \frac{Total}{Items}$

Make Total the Subject of formula

$Total = Mean * Items$

$Total = \$4.44 * 11$

$Total = \$48.84$

When the 12th item of $39.99 is added, the new mean becomes.

$New\ Mean = \frac{Total + \$39.99}{11 + 1}$

$New\ Mean = \frac{\$48.84 + \$39.99}{11 + 1}$

$New\ Mean = \frac{\$88.83}{12}$

$New\ Mean = \$7.4025$

By comparing this the old mean, we can see a huge increment between $4.44 and $7.4025

This means that there will be a big difference in the mean when the new item is added.

For the Median:

The old mean shows that the prices of the 11 items is within a small range from $4.44.

So, when the new item is added the median will only change a little bit.

In other words, the median value will only change a little bit.

7 0

3 years ago

Read 2 more answers

What is the answer to this problem that I am having trouble with?

Gnesinka [82]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

Read the values from the graph in the usual way: find the x-coordinate, then locate the point on the graph and find its y-coordinate.

You find the y-coordinate by following the horizontal line to the y-axis, where the numbers are.

4 0

3 years ago

Find the following limit or state that it does not exist. ModifyingBelow lim With x right arrow minus 2 StartFraction 3 (2 x min

leva [86]

Answer:

-60

Step-by-step explanation:

The objective is to state whether or not the following limit exists

$\lim_{x \to -2} \frac{3(2x-1)^2 - 75}{x+2}$ .

First, we simplify the expression in the numerator of the fraction.

$3(2x-1)^2 -75 = 3(4x^2 - 4x +1) -75 = 12x^2 - 12x + 3 - 75 = 12x^2 - 12x -72$

Now, we obtain

$12(x^2-x-6) = 12(x+2)(x-3)$

and the fraction is transformed into

$\frac{3(2x-1)^2 - 75}{x+2} = \frac{12(x+2)(x-3)}{x+2} = 12 (x-3)$

Therefore, the following limit is

$\lim_{x \to -2} \frac{3(2x-1)^2 - 75}{x+2} = \lim_{x \to -2} 12(x-3) = 12 \lim_{x \to -2} (x-3)$

You can plug in $-2$ in the equation, hence

$12 \lim_{x \to -2} (x-3) = 12 (-2-3) = -60$

6 0

4 years ago