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Answer:
The p-value of the test is 0.1515.
Step-by-step explanation:
The hypothesis for the test can be defined as follows:
<em>H</em>₀: The mean level of arsenic is 80 ppb, i.e. <em>μ</em> = 80.
<em>Hₐ</em>: The mean level of arsenic is greater than 80 ppb, i.e. <em>μ</em> > 80.
As the population standard deviation is not known we will use a t-test for single mean.
It is provided that the sample mean was, .
The adjusted sample provided is:
S = {57, 64, 70, 82, 84, 123}
Compute the sample standard deviation as follows:
Compute the test statistic value as follows:
Thus, the test statistic value is 1.148.
Compute the p-value of the test as follows:
*Use a t-table.
Thus, the p-value of the test is 0.1515.
Decision rule:
If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
p-value = 0.1515 > α = 0.05
The null hypothesis will not be rejected at 5% level of significance.
Thus, concluding that the mean level of arsenic in chicken from the suppliers is 80 ppb.