Question

A rod 30 cm long moves in a plane perpendicular to a magnetic field of 505 G. The velocity of the rod is perpendicular to its length. Find the speed of the rod if the potential difference between the ends is 6 V.

Answer 1

Answer:

Speed, v = 396.03 m/s

Explanation:

It is given that,

Length of the rod, l = 30 cm = 0.3 m

Magnetic field, $B = 505\ G=0.0505\ T$

The potential difference between the ends is 6 V, E = 6 V

The rod moves in a plane perpendicular to a magnetic field with some speed. Due to this motion an emf is induced it it. It is given by :

$\epsilon=Blv$

Where

v is the speed of rod

$v=\dfrac{\epsilon}{Bl}$

$v=\dfrac{6}{0.0505\times 0.3}$

v = 396.03 m/s

So, the speed of the rod is 396.03 m/s. Hence, this is the required solution.