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Yanka [14]
3 years ago
10

How high off the ground is a a book that has 120 J of potential energy and a 4-kg mass ​

Physics
1 answer:
RoseWind [281]3 years ago
7 0
<h2><em><u>Answer:</u></em></h2><h2><em><u>Answer:hdjfghshdhdjdjdjdiiiid</u></em></h2><h2><em><u>Answer:hdjfghshdhdjdjdjdiiiidExplanation:</u></em></h2><h2><em><u>Answer:hdjfghshdhdjdjdjdiiiidExplanation:jjejeej!jwddhhehehehryrhrrhehrjrjejejddjejeejbdbndndjdjfhfhfjddjfjfjudk!ejfjffjfjffjjdiekpskeurhfhjfhdjfjfjfjfjfnfffjfnfnfjfngbfbfnfjffffjfjfj\fmcnckffklflfkfikktkfkfkkkotkfktktktktktkttdrproekeeeeeeeeke</u></em></h2>
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A cabbie is trying to stop when he notices a fare is whistling them over. The
liberstina [14]
  • K.E=18750J
  • Mass=m=2100kg
  • Velocity=v

\boxed{\sf K.E=\dfrac{1}{2}mv^2}

\\ \sf\longmapsto 18750=\dfrac{1}{2}2100v^2

\\ \sf\longmapsto 18750=1050v^2

\\ \sf\longmapsto v^2=\dfrac{18750}{1050}

\\ \sf\longmapsto v^2=17.85m^2

\\ \sf\longmapsto v=\sqrt{17.85}

\\ \sf\longmapsto v=4.1m/s

7 0
3 years ago
MIDDLE SCHOOL SCIENCE<br> yee yee please answer 6, 7, and 8
Nikolay [14]

Answer:

what r the questions i can’t see them

Explanation:

5 0
3 years ago
Newton’s 3rd law of motion states that “every action has an equal and opposite reaction.” A golf ball was hit with a force of 20
DedPeter [7]

Answer:

<u>Example of Newton's III law</u>

  • In the, golf the ball was hit by a club with certain force. As the club hits the ball it's the action. When the ball flies away its the reaction.
  • When a person swings a golf club at the ball, when it hits the ball, it causes the ball to roll up the face of the club and into the air towards the target.
8 0
3 years ago
A body is thrown up with a velocity of 78.4 m per second.How high will it rise and how much time it will take to return to its p
a_sh-v [17]

Answer:

The maximum height reached by the body is 313.6 m

The time to return to its point of projection is 8 s.

Explanation:

Given;

initial velocity of the body, u = 78.4 m/s

at maximum height (h) the final velocity of the body (v) = 0

The following equation is applied to determine the maximum height reached by the body;

v² = u² - 2gh

0 = u² - 2gh

2gh = u²

h = u²/2g

h = (78.4²) / (2 x 9.8)

h = 313.6 m

The time to return to its point of projection is calculated as follows;

at maximum height, the final velocity becomes the initial velocity = 0

h = v + ¹/₂gt²

h = 0 + ¹/₂gt²

h =  ¹/₂gt²

2h = gt²

t² = 2h/g

t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 313.6}{9.8} }\\\\t = 8 \ s

4 0
3 years ago
Assume that two of the electrons at the negative terminal have attached themselves to a nearby neutral atom. There is now a nega
devlian [24]

Answer: its negative

Explanation: becase it is

5 0
3 years ago
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