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hram777 [196]
3 years ago
15

A stun gun or TASER is designed to put out a few seconds worth of electric pulses that impress a

Physics
1 answer:
iren [92.7K]3 years ago
5 0

Answer:

Resistance = 400000 Ohms

Explanation:

Given the following data;

Voltage = 1200 V

Current = 3 mA = 3/1000 = 0.003 A

To find the resistance;

Voltage = current * resistance

Resistance = 1200/0.003

Resistance = 400000 Ohms

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A uniform electric field of magnitude 375 n/c pointing in the positive x - direction acts on an electron, which is initially at
Finger [1]
(a) The force exerted by the electric field on the electron is given by the product between the electron charge q and the intensity of the electric field E:
F=qE=(1.6 \cdot 10^{-19}C)(375 N/C)=6\cdot 10^{-17}N
Under the action of this force, the electron moves by:
\Delta x = 3.20 cm=0.032 m
And the work done by the electric field on the electron is equal to the product between the magnitude of the force and the displacement of the electron. The sign has to be taken as positive, because the direction of the force is the same as the displacement of the electron, so:
W=F \Delta x= (6\cdot 10^{-17}N)(0.032 m)=1.9 \cdot 10^{-18}J

(b) The electron is initially at rest and it starts to move under the action of the electric field. This means that as it moves, it acquires kinetic energy and it loses potential energy. The change in potential energy is the opposite of the work done by the electric field:
\Delta U = U_f - U_i = -1.9 \cdot 10^{-18} J
Where Uf and Ui are the final and initial potential energy of the electron.

(c) For the conservation of energy, the sum of the kinetic energy and potential energy of the electron at the beginning of the motion and at the end must be equal:
U_i + K_i = U_f + K_f (1)
where Ki and Kf are the initial and final kinetic energies.
The electron is initially at rest, so Ki =0, and we can rewrite (1) as 
U_i - U_f = - \Delta U = K_f = \frac{1}{2}m_e v_f^2
and by using the mass of the electron me, we can find the value of the final velocity of the electron:
v_f= \sqrt{ -\frac{2 \Delta U}{m_e} }= \sqrt{- \frac{2(-1.9 \cdot 10^{-18} J)}{9.1 \cdot 10^{-31} kg} } =2.04 \cdot 10^6 m/s



7 0
3 years ago
A 5.1kg iron skillet is heated to 373K from an initial temperature of 295K. How much thermal energy was transferred?
posledela

Answer:

the thermal energy transferred is 183,226.68 J

Explanation:

Given;

mass of iron skillet, m = 5.1 kg

initial temperature, t₁ = 295 K

final temperature, t₂ = 373 K

The thermal energy transferred is calculated as;

Q = mcΔt

where;

Δt is change in temperature, = t₂ - t₁

c is specific heat capacity of iron = 460.6 J/kg.K

Q = 5.1 x 460.6 x (373 - 295)

Q = 183,226.68 J

Therefore, the thermal energy transferred is 183,226.68 J

6 0
3 years ago
When we greatly dim the light used in a double-slit experiment, we don’t simply get a dimmer interference pattern. What do we ge
maw [93]

Answer:

....... ....................

8 0
3 years ago
Where on the periodic table would this element most likely be found? Group 1 Group 2 Group 12 Group 13
andrezito [222]

Answer:

The right approach will be Option C "Group 12".

Explanation:

  • A table that further arranges the chemical components in addition to expanding the electron configuration. Elements possessing identical characteristics are positioned in almost the same section (column or group), although elements in almost the same row become positioned with a similar amount of electron spheres.
  • Group 12 components therefore partially replaced (n − 1)d subshells, and therefore aren't metals, technically accurate. However, although much their chemistry seems to be comparable to something like the components throughout the d block which includes establishing themselves.

Some other options in question are not relevant to something like the given scenario. Because then the option here is just the right one.

6 0
3 years ago
Which option is an example of chemical energy being transformed into thermal energy?
mylen [45]

Answer:

d

Explanation:

3 0
3 years ago
Read 2 more answers
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