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3 years ago

Break down of rock can be chemical or mechanical

Physics

2 answers:

lisabon 2012 [21]3 years ago

7 0

Mechanical I think is the answer I'm not really sure

34kurt3 years ago

3 0

Chemical weathering can break down rock.

So, (Chemical Weathering will be your answer.)

Have a Brainly Day!

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Two 2.00 cm * 2.00 cm plates that form a parallel-plate capacitor are charged to { 0.708 nC. What are the electric field strengt

lisov135 [29]

Answer:

(a) $E=200000Volts/meter$

(b) $E=200000Volts/meter$

Explanation:

Given data

Area A=4.0 cm²=0.0004 m²

Electric permittivity ε=8.854×10⁻¹² farads/meter

Charge q=0.708 nC

To find

(a) Potential at distance=1.00mm

(b) Potential at distance=2.00mm

Solution

For (a) Potential at distance=1.00mm

First we need to find the capacitance

$C=E*A/D\\C=8.854*10^{-12}*(0.0004/1.00*10^{-3} )\\ C=3.5416*10^{-12}farads$

As we know that

$Q=CV\\V=Q/C\\V=(0.708*10^{-9}C )/3.5416*10^{-12}farads\\V=200Volts$

So Electric potential is given as:

$E=V/d\\E=(200V)/(1*10^{-3}m )\\E=200000Volts/meter$

For (b) Potential at distance=2.00mm

First we need to find the capacitance

$C=E*A/D\\C=8.854*10^{-12}*(0.0004/2.00*10^{-3} )\\ C=1.7708*10^{-12}farads$

As we know that

$Q=CV\\V=Q/C\\V=(0.708*10^{-9}C )/1.7708*10^{-12}farads\\V=400Volts$

So Electric potential is given as:

$E=V/d\\E=(400V)/(2.0*10^{-3}m )\\E=200000Volts/meter$

7 0

4 years ago

Solvent that can be used to remove ink from clothes and cleaning greasy<br> hands

Vlad1618 [11]

Answer: that’s chemistry not physics

Explanation:

7 0

3 years ago

Read 2 more answers

You decide to travel by car for your holiday visits this year. You leave early in the morning to avoid congestion on the roads.

Bond [772]

Answer:

$d_t=266.918\ miles$ is the total distance of the trip travelled.

$s_{avg}=54.7895\ mph$ is the average speed of the journey

Explanation:

Given:

duration of first interval, $t_1=3.22\ hr$

speed during the first interval, $v_1=65.9\ mph$

duration of stoppage, $t_0=42.1\ min=0.7017\ hr$

duration of second interval, $t_2=0.95\ hr$

speed during second interval, $v_2=57.6\ mph$

<u>Now the total distance travelled:</u>

$\rm distance=speed\times time$

$d_t=v_2.t_2+v_1.t_1$

$d_t=57.6\times 0.95+65.9\times 3.22$

$d_t=266.918\ miles$

<u>The average speed:</u>

$\rm speed_{avg}=\frac{total\ distance}{total\ time\ taken}$

$s_{avg}=\frac{d_t}{(t_0+t_1+t_2)}$

$s_{avg}=\frac{266.918}{(0.7017+3.22+0.95)}$

$s_{avg}=54.7895\ mph$

4 0

4 years ago

body starting from rest and moving with an uniform acceleration of 3 m/s²..What is its velocity after 15s?

Luba_88 [7]

<h2>Answer :</h2>

□ The Final velocity of body = 45 m/s $\sf{ }$

<h2>Given :</h2>

Initial velocity of body = 0 m/s

Acceleration of body = 3 m/s²

Time taken by body = 15 sec

<h2>To Calculate :</h2>

Final velocity of body = ?

<h2>How To Calculate ?</h2>

Here in this question we are provided that a body is in rest so it's initial velocity will be 0 m/s (because from rest), Acceleration of body is 3 m/s², and Time taken is also given which is 15 sec.

To calculate the Final velocity of body we'll use the first equation of motion which says v = u + at

Where,

v is the Final velocity in m/s.

u is the Initial velocity in m/s.

a is the Acceleration in m/s².

t is the Time taken in second.

<h2>Calculation :</h2>

From first equation of motion

⇒ v = u + at

⇒ v = 0 + 3 × 15

⇒ v = 0 + 45

⇒ v = 45

Hence, the Final velocity of body is 45 m/s.

7 0

3 years ago

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Which Law is connected with inertia?

Ilya [14]

Newton's first law of motion is connected with inertia :)

6 0

3 years ago

Read 2 more answers