F(x)=x^2+3x+5
f(3+h)=(3+h)^2+3(3+h)+5
f(3+h)=9+6h+h^2+9+3h+5
f(3+h)=23+9h+h^2
Answer:
the correct anwser is B................
No solution (D)
Answer = -1
Hello, the answer should be A,B and D options.
First, let's edit the given equations option-by-option.
<h2>Option A:</h2>




There is only one solution which is
.
<h2>Option B:</h2>




There is only one solution which is
.
<h2>Option C:</h2>



In Math, zero is <u>not equal to</u> minus twenty four (
) that's why we do not have any solution in this equation.
<h2>Option D:</h2>




There is only one solution which is 
we know the diameter of the circle is 54, so the radius of it is half that or 27.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=27 \end{cases}\implies A=\pi (27)^2\implies \stackrel{using~\pi =3.14}{A=2289.06~mi^2}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D27%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2827%29%5E2%5Cimplies%20%5Cstackrel%7Busing~%5Cpi%20%3D3.14%7D%7BA%3D2289.06~mi%5E2%7D)