Correct Answer: Mass of ore that contains 200 g of Ti is
617.28 g.
Reason:
Given: Ore contains 32.4% Ti by mass.
It implies that, 100 g of ore ≡ 32.4 g of Ti
Therefore, x g of ore ≡ 200 g of Ti
Thus, x =
Hence, mass of ore that contains 200 g of Ti is
617.28 g.
Distribute the 5 to the (x-9), which leaves you with:
5x - 45 = 5x
Subtract 5x from both sides.
This leaves you with:
-45 = 0
which is false, meaning there is no solution to this problem.
The answer is A. No solution
Answer is: 4.02 <span>grams of water are required.
</span>Chemical reaction: BaH₂ + 2H₂O → Ba(OH)₂ + 2H₂.
Ideal gas law: p·V =
n·R·T.<span>
p = 755 mm Hg </span>÷ 760.0 mmHg / atm = 0.993<span> atm.
T = 25 + 273.15 = 298.15 K.
V(H</span>₂) <span>= 5.50 L.
R = 0,08206 L·atm/mol·K.
n(H</span>₂)
= <span>0.993 atm · 5.5 L ÷ 0,08206 L·atm/mol·K · 298.15 K.
n(H</span>₂)
= 0.223 mol.<span>
From chemical reaction: n(H</span>₂O) : n(H₂) = 1 : 1.<span>
n</span>(H₂O) = 0.223 mol.<span>
m</span>(H₂O) =
0.223 mol · 18 g/mol.<span>
m</span>(H₂O) =
4.02 g.
Answer:
Significant figures are a measure of <u><em>precision</em></u>.
Explanation:
The significant figures of a number are those that have a real meaning and, therefore, provide some information. Therefore, the set of digits that are known with certainty in a measure are called significant figures and are the digits of a number considered non-null.
Any experimental measurement is inaccurate and must be expressed with its significant figures.
In this way, significant figures express the precision of a measuring tool.