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Bad White [126]
3 years ago
6

Please help!!!!! Why is a spectrum for a given element unique for that element? A. No element has more than two electrons in the

first shell. B. Each element has a unique arrangement of electrons. C. Atoms of different elements have different masses. D. Atomic nuclei contain no electrons.
Chemistry
2 answers:
erik [133]3 years ago
5 0
I think that the best scientific answer would be.....
Anon25 [30]3 years ago
3 0
The correct answer for this question is B.
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T. Svedberg measured the molecular weight of carbonyl hemoglobin by velocity centrifugation. In this experiment, 0.96 g of prote
Natalija [7]

Answer:

The molecular weight is 77.7 kg/mol

Explanation:

The molecular mass of hemoglobin is equal to:

M=\frac{RTs}{D(1-Vp)}

Where

R = molar gas constant = 8.315 J/K mol

p = density = 0.998 g/mL

V = specific volume = 0.755 mL/g

s = sedimentation rate = ?

D = diffusion rate = 7x10⁻¹¹m²/s

T = temperature = 303 K

The sedimentation rate is equal to:

s=\frac{1}{w^{2}t } ln(\frac{x_{b,t} }{x_{b,0} } )

Where

w = angular velocity = 39300 rpm = 246929.18 rad/min

xb,30 = boundary midpoint distance at 30 min = 4.525 + 0.074 cm

t = time = 30 min

xb,0 = boundary midpoint distante at 0 min = 4.525 cm

s=\frac{1}{246929.18^{2}*30 } ln(\frac{4.525+0.074}{4.525} )=8.87x10^{-13} min=5.32x10^{-13} s

The molecular weight is:

M=\frac{8.315*303*5.32x10^{-13} }{7x10^{-11}*(1-(0.755*0.998)) } =77.7kg/mol

5 0
3 years ago
Determine the value of the equilibrium constant, Kgoal, for the reaction CO2(g)⇌C(s)+O2(g), Kgoal=? by making use of the followi
marta [7]

Answer : The value of K_{goal} for the final reaction is, 1.238\times 10^{-7}

Explanation :

The following equilibrium reactions are :

(1) 2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2 K_1=5.40\times 10^{-16}

(2) 2H_2(g)+O_2(g)\rightleftharpoons 2H_2O(l) K_2=1.06\times 10^{10}

(3) CH_3COOH(l)\rightleftharpoons 2C(s)+O_2(g) K_3=2.68\times 10^{-9}

The final equilibrium reaction is :

CO_2(g)\rightleftharpoons C(s)+O_2(g) K_{goal}=?

Now we have to calculate the value of K_{goal} for the final reaction.

First half the equation 1, 2 and 3 that means we are taking square root of equilibrium constant and then add all the equation 1, 2 and 3 that means we are multiplying all the equilibrium constant, we get the final equilibrium reaction and the expression of final equilibrium constant is:

K_{goal}=\sqrt{K_1\times K_2\times K_3}

Now put all the given values in this expression, we get :

K_{goal}=\sqrt{(5.40\times 10^{-16})\times (1.06\times 10^{10})\times (2.68\times 10^{-9})}

K_{goal}=1.238\times 10^{-7}

Therefore, the value of K_{goal} for the final reaction is, 1.238\times 10^{-7}

3 0
3 years ago
A salt contains only magnesium and one of the halide ions. A 0.0776-g sample of the salt was dissolved in water, and an excess o
sdas [7]

Answer:

The formula of the magnesium halide is MgF₂

Explanation:

All halides, X, produce a salt with Mg with the formula:

MgX₂

<em>-There are 2 moles of the halide ion per mole of Mg-</em>

<em />

With the mass of the MgSO₄ we can find moles of magnesium sulfate  = Moles Mg.

With moles of Mg we can know the moles of the halide -1 mole Mg = 2 moles of Halide-

And we can find the mass of Mg in the 0.0776g sample. Subtracting we can find the mass of the halide and, with the mass and moles of the halide we can find its molecular weight and its identity:

<em>Moles MgSO₄ -Molar mass: 120.366g/mol- = Moles Mg:</em>

0.150g * (1mol / 120.366g) = 1.2462x10⁻³ moles Mg

<em>Moles halide:</em>

1.2462x10⁻³ moles Mg * 2 = <em>2.4924x10⁻³ moles Halide</em>

<em>Mass Mg -Molar mass: 24.305g/mol:</em>

1.2462x10⁻³ moles Mg * (24.305g / mol) = 0.0303g Mg

<em>Mass halide:</em>

0.0776g - 0.0303g Mg = <em>0.0473g</em>

<em>Molecular weight of the halide:</em>

0.0473g / 2.4924x10⁻³ moles =

18.98g/mol

This molecular weight is the molecular weight of Fluoride ion, F⁻,

<h3>The formula of the magnesium halide is MgF₂</h3>
6 0
3 years ago
Which types of reactions would result in the formation of precipitate?
IRINA_888 [86]

Answer:

Double Displacement Reaction

Explanation:

A double displacement reaction is a type of chemical reaction in which the reactant ions exchange places to form new products. Usually, a double displacement reaction results in precipitate formation.

8 0
3 years ago
A 3.00 L flexible container holds a sample of hydrogen gas at 153 kPa. If the pressure increases to 203 kPa and the temperature
dybincka [34]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

 

P1V1 =P2V2

V2 = P1 V1 / P2

V2 = 153 x 3.00 / 203

<span>V2 = 2.26 L</span>

3 0
2 years ago
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