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damaskus [11]
3 years ago
7

When ethyl acetoacetate (ch3coch2co2ch2ch3) is treated with one equivalent of ch3mgbr, a gas is evolved from the reaction mixtur

e, and after adding aqueous acid, ethyl acetoacetate is recovered in high yield. identify the gas formed and explain why the starting material was recovered in this reaction. be sure to answer all parts?

Chemistry
1 answer:
pashok25 [27]3 years ago
6 0
The protons of methylene group between the two carbonyl groups in ethylacetoacetate are acidic in nature. When compounds containing such acidic protons are treated with bases the loose proton and form enolates.

In this particular example when ethylacetoacetate is reacted with methyl magnesium bromide, the methyl group abstracts the acidic proton and converts into methane gas. The enolate when hydrolyzed is again converted into ethylacetoacetate as shown below,

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Create a graphic representation that illustrates the steps from gene to protein. Label and describe each step.
Vesna [10]

Okay so,

1) Translation- show the RNA strand attatching to a DNA strand with the complimentary base pairs. introns are spliced

2) mRNA leaves the cell and joins with a ribosome

3) Transcription - tRNA (clover shaped) reads each codon (triplets) which each code for an amino acid. The stop codons on the end tell the tRNA that the chain is finished

4) the sequence forms the primary structure (all peptide bonds) which determines the shape of the secondary (hyrdogen and peptide) and hence determines the shape of the tertiary structure of a protein (ionic, hydrogen, disulfide bridges and hydrophibic interactions)


Hope this helps :)

6 0
3 years ago
Which of the following statements is true?
Wittaler [7]

Answer:

Metals lose electrons to become cations.

Explanation:

For example, sodium loses an electron to become a sodium cation.

Na· ⟶ Na⁺ + e⁻

A is <em>wrong</em>. Nonmetals gain electrons to become anions.

B is <em>wrong</em>. Metals lose electrons.

D is <em>wrong</em>. Nonmetals gain electrons to become anions.

8 0
4 years ago
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wlad13 [49]

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Explanation:

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Nevertheless, Ru does not form Ru(I) compounds and few Ru(II) compounds (RuCl2, RuBr2, RuI2). It also forms Ru(III)Cl3 and a larger number of Ru(IV) compounds, e.g. RuO2, RuS2. It also forms RuO4

3 0
3 years ago
I’ll give 5 stars and Brainliest plus this is 20 points lol
Daniel [21]

Answer:

I think is b

Explanation:

4 0
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dezoksy [38]

Answer:

I guess 3 to be honest and that's what I think

4 0
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