To solve this problem we will apply the concepts of acceleration according to the laws of kinetics. Acceleration can be defined as the change in velocity per unit time, that is,
Here,
v = Final velocity
u = Initial velocity
t = Time
Rearranging to find the initial velocity,
Now the acceleration is equal to the gravity, then,
The velocity of the shell at 5.5s after the launch is,
Therefore the magnitude of the velocity of the shell at 5.5s is -19.26m/s
Answer: 1. h
Explanation:
The block would reach exactly the same height from the ground. It would travel a greater distance away from the source, but the height away from the earth would remain the same as you are giving it the same energy each time. Therefore, it will reach the same gravitation potential energy.
Another approach to look at it this is seeing it when the Block moves up the slope, its kinetic energy decreases and the potential energy increases. In both cases, the kinetic energy decreases by same amount, therefore the block rises to same height H.
Try to use the formula;
1/2MV2 = mgh
Where V = √(2gh)
I hope this helps
Answer:
4.351968e+17 seconds
Explanation:
So I googled age of the universe and it says 13.8 billion years.
you'll have to do some conversions:
in one year, there are 365 days. in one day, there are 24 hours. in one hour, there are 3600 seconds.
so you have to add in the current age of the universe to that equation:
arranged so that the proper "units" will read as "x seconds" at the end of the equation.
then you do the math to find x:
13.8 billion x 365 x 24 x 3600 = 4.351968e+17 seconds.
which would be 435,196,800,000,000,000 seconds
Hope this helps :)