Answer:
Thrust developed = 212.3373 kN
Explanation:
Assuming the ship is stationary
<u>Determine the Thrust developed</u>
power supplied to the propeller ( Punit ) = 1900 KW
Duct distance ( diameter ; D ) = 2.6 m
first step : <em>calculate the area of the duct </em>
A = π/4 * D^2
= π/4 * ( 2.6)^2 = 5.3092 m^2
<em>next : calculate the velocity of propeller</em>
Punit = (A*v*β ) / 2 * V^2 ( assuming β = 999 kg/m^3 ) also given V1 = 0
∴V^3 = Punit * 2 / A*β
= ( 1900 * 10^3 * 2 ) / ( 5.3092 * 999 )
hence V2 = 8.9480 m/s
<em>Finally determine the thrust developed </em>
F = Punit / V2
= (1900 * 10^3) / ( 8.9480)
= 212.3373 kN
I had to look for the options and here is my answer:
Given that a guitar string has a basic frequency of 500hz, the frequency that can be set for this into resonant vibration would be 1500 Hz. The resonant vibration here is necessary in musical instruments because it delivers a vibrating system which leads to a higher amplitude at a particular frequency.
Answer:
The magnitude of the resultant vector R is 50 meters ⇒ 2nd answer
Explanation:
<u><em>The resultant vector</em></u> is the vector sum of two or more vectors
If the two vectors perpendicular to each other, then the magnitude of
the resultant vector is the square root of the sum of their squares
If x and y are two vectors perpendicular to each other, then the
magnitude of its resultant vector R is:
→ 
Lets solve the problem
A right triangle with the base labeled 40 meters and the height labeled
30 meters
The hypotenuse is a dotted arrow labeled R
→ The base and the height of the right triangle are perpendicular
→ The hypotenuse is the resultant vector of them
Assume that x represents the base of the triangle and y represents the
height of it
By using the rule above
→ x = 40 m , y = 30 m
→ 
→ 
→ 
→ 
<em>The magnitude of the resultant vector R is 50 meters</em>
Answer:
Explanation:
Expression for times period of a satellite can be given as follows
Time period T = 1.8 x 60 x 60
= 6480
T² =
where T is time period , r is radius of orbit , G is gravitational constant and M is mass of the satellite.
6480² = 4 x 3.14² x 7.5³ x 10¹⁸ / GM
GM = 4 x 3.14² x 7.5³ x 10¹⁸ / 6480²
= 3.96 X 10¹⁴
Expression for acceleration due to gravity
g = GM / R² where R is radius of satellite
20 = 3.96 X 10¹⁴ / R²
R² = 3.96 X 10¹⁴ / 20
= 1.98 x 10¹³ m
R= 4.45 x 10⁶ m
Answer:
t=0.417s
Explanation:
After the ball hits the racket it is in freefall(assume air resistance as negligible)
so a=-g
use
x-x0=v0t+1/2at^2
Plug in givens
20=50t-4.9t^2
Solve quadratic equation using quadratic formula
t= 0.417 seconds, (the other answer is extraneous because it is too big because in 1 second, the ball travels 50 meters)