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Rus_ich [418]
3 years ago
11

During light activity, a 70-kg person may generate 200 kcal

Physics
1 answer:
Lerok [7]3 years ago
3 0

Answer:

2.75387\ ^{\circ}

Explanation:

m = Mass of person = 70 kg

c = Specific heat of human body = 0.83\ J/kg^{\circ}C

\Delta T = Change in temperature

Time taken is 1 hour

Heat is given by

Q=mc\Delta T\\\Rightarrow \Delta T=\dfrac{Q}{mc}\\\Rightarrow \Delta T=\dfrac{0.8\times 200\times 1}{70\times 0.83}\\\Rightarrow \Delta T=2.75387\ ^{\circ}C

The rise in temperature is 2.75387\ ^{\circ}C

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A sealed container holding 0.0255 L of an ideal gas at 0.981 atm and 65 ∘ C is placed into a refrigerator and cooled to 41 ∘ C w
user100 [1]

Answer:

0.911 atm

Explanation:

In this problem, there is no change in volume of the gas, since the container is sealed.

Therefore, we can apply Gay-Lussac's law, which states that:

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p\propto T

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For a gas undergoing a transformation, the law can be rewritten as:

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where in this problem:

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T_1=65^{\circ}+273=338 K is the initial absolute temperature of the gas

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Solving for p2, we find the final pressure of the gas:

p_2=\frac{p_1 T_2}{T_1}=\frac{(0.981)(314)}{338}=0.911 atm

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