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tatyana61 [14]
3 years ago
13

When a particle of mass m is at (x comma 0 )​, it is attracted toward the origin with a force whose magnitude is StartFraction y

Over x squared EndFraction . If the particle starts from rest at x equals b and is acted upon by no other​ forces, find the work done on it by the time it reaches x equals a​, 0 less than a less than b.
Physics
1 answer:
Dahasolnce [82]3 years ago
8 0

Answer:

W = y (b-a) / ab

Explanation:

Work is defined by the expression

W = ∫ F. dr

In this case the force is in the same direction of displacement, so the scalar product is reduced to the ordinary product

W = ∫ F dr

The expression of the strength left is

F = -y / x²

let's replace and integrate

W = ∫ (-y / x²) dx

W = -y (-1 / x)

We evaluate between the lower limit x = b + a to the upper limit x = 0 + a

W = -y (-1 / b + 1 / a)

W = y (b-a) / ab

where (b-a) is the distance traveled

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From i and ii, we have:

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r=\frac{75J}{(7.2\times 10^{-5}C)(4.8\times 10^5 V/m)}\\\\=2.1701\approx2.2\ m

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