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4 years ago

13

Which term describes how fast the atoms or molecules inside an object are moving?

1 answer:

IrinaVladis [17]4 years ago

3 0

Im pretty sure it’s A. temperature

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Look at the photo and answer the question

Naddik [55]

Answer:

I think D. maybe C

Explanation:

newtons is force of gravity and grams can be weight or mass in the metric system

5 0

3 years ago

Read 2 more answers

You drop a rock off of a cliff at exactly the edge after 25 seconds exactly you hear a splash your physics friend tells you the

Reptile [31]

The speed of sound is 340.29 meters per second.

Knowing that, we can calculate how high this cliff is by 340.29 * .4

The cliff is 340.29 * .4 = 136.12 meters

8 0

4 years ago

If a small motor does 520 J of work to move a toy car 260 m, what force does the engine exert on the car?

ohaa [14]

Answer:

<h2>2 N</h2>

Explanation:

The force engine exert on the car can be found by using the formula

$f = \frac{w}{d} \\$

w is the workdone

d is the distance

From the question we have

$f = \frac{520}{260} = 2 \\$

We have the final answer as

<h3>2 N</h3>

Hope this helps you

4 0

3 years ago

What is the outermost structure in a plant cell

dybincka [34]

Molecular structure of the primary cell wall in plants. Up to three strata or layers may be found in plant cell walls: The middle lamella, a layer rich in pectins. This outermost layer forms the interface between adjacent plant cells and glues them together.

5 0

3 years ago

Find the total change in the internal energy of a gas that is subjected to the following two-step process. In the first step the

agasfer [191]

Answer:

U = 9253.6 J

Explanation:

It is given that,

Heat transferred in isochoric process, $Q_1=5560\ J$

Pressure in this process, $P_1=3.32\times 10^5\ Pa$

In the second step,

It is subjected to isobaric compression until its volume decreases by, $V=-7.3\times 10^{-3}\ m^3$ (it decreases)

Heat transferred out of the gas, $Q_2=1270\ J$

In isochoric process, work done by the gas is zero as in this type volume is constant, $W_1=0$

According to first law of thermodynamics,

$\Delta U=Q-W$

$\Delta U_1=5560\ J$ .............(1)

In isochoric compression, $W_2=P\Delta V$

$\Delta U_2=1270-3.32\times 10^5\times (-7.3\times 10^{-3})$

$\Delta U_2=3693.6\ J$

Let U is the total change in the internal energy of this gas. So,

$U=U_1+U_2$

$U=5560+3693.6$

U = 9253.6 J

So, the total change in the internal energy of this gas is $$9253.6 J. Hence, this is the required solution.

7 0

3 years ago