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densk [106]
3 years ago
13

A tennis player smashes a ball of mass m horizontally at a vertical wall. The ball rebounds at the same speed v with which it st

ruck the wall. Has the momentum of the ball changed, and if so, by how much?
A. 4mv
B.0
C.mv
D.0.5mv
E.2mv
Physics
1 answer:
Morgarella [4.7K]3 years ago
5 0

Answer:

<em> B.0</em>

Explanation:

Change in momentum: This is defined as the product of mass and change in velocity of a body. or it can be defined as the product of force and time of a body. The fundamental unit of change in momentum is kg.m/s

Change in momentum = M(V-U)......................... Equation 1

where M = mass of the ball, V = final velocity of the ball, U = initial velocity of the ball.

Let: M = m kg and V = U = v m/s

Substituting these values into equation 1

Change in momentum = m(v-v)

Change in momentum = m(0)

Change in momentum = 0 kg.m/s

<em>Therefore the momentum of the ball has not changed.</em>

<em>The right option is B.0</em>

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Answer:

1.27\times 10^{12}\Omega/m

Explanation:

We are given that

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Using 1\mu m=10^{-6} m

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Resistance =R=2\times 10^5\Omega cm^2

Internal specific resistance=r=100 ohm cm=100\times \frac{1}{100}\Omega-m=1\Omega m

Using 1 m=100 cm

Internal resistance per unit length=\frac{r}{A}=\frac{1}{\pi r^2}=\frac{1}{3.14\times (0.5\times 10^{-6})^2}=1.27\times 10^{12}\Omega/m

Using \pi=3.14

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8 0
3 years ago
The magnetising current in a transformer is rich in ______________ harmonic?
sukhopar [10]
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Answer:

Explanation:

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b )

k = 4.5 x 10¹ = 45 N/m

Stored energy = 1/2 k x² = .5 x 45 x 8² x 10⁻⁴ =1440 x 10⁻⁴ J

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