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Kryger [21]
3 years ago
14

A spaceship of 3.20 x 10*7kg travels around another planet, of

Physics
1 answer:
vfiekz [6]3 years ago
4 0

Answer:

answer d

Explanation:

It would be asnwer d because you need. to multiople both numbers 3.20x10*7 and 6.34x10^25 then multiple.  

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A car is travelling at a velocity of 20m/s. After 30sec it covers a distance of 1200 m. Calculate the acceleration of the car an
Umnica [9.8K]

Answer:

Acceleration: a = 1,3333 \frac{m}{s^{2} }

Final velocity: v = 60 \frac{m}{s}

Explanation:

To calculate the acceleration, you start from the formula:

s = v_i t+\frac{1}{2}at^{2}

Thus:

a = \frac{ 2(s - v_it)}{t^{2}}

Now that you have the accelration, you can use the this formula to calculate the final speed:

a = \frac{v_f - v_i}{\Delta t}

Thus:

v_f = a \Delta t + v_i

8 0
3 years ago
What is paleomagnetism how has it been used to understand plate tectonics?
Nonamiya [84]
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8 0
4 years ago
Which of the following elements of writing is defined as the choice of words sulted to the type of writing?
pantera1 [17]

Answer:

Diction

Explanation:

is defined as the choice of words suited to the type of writing. hope this helps you :)

5 0
3 years ago
Read 2 more answers
A 565 N rightward force pulls a large box across the floor with a constant velocity of 0.75 m/s. If the coefficient of friction
alukav5142 [94]
The first thing you should know is that the friction force is equal to the coefficient of friction due to normal force.
 Therefore, clearing the normal force we have:
 The friction is 565N.
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6 0
4 years ago
Three identical resistors are connected in parallel to a battery. If the current of 12. A flows from the battery, how much curre
Doss [256]

Answer:

4 A

Explanation:

We are given that

R_1=R_2=R_3=4\Omega

I=12 A

We have to find the current flowing through each resistor.

We know that in parallel combination current flowing through different resistors are different and potential difference across each resistor is same.

Formula :

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

Using the formula

\frac{1}{R}=\frac{1}{4}+\frac{1}{4}+\frac{1}{4}=\frac{3}{4}

R=\frac{4}{3}\Omega

V=IR

Substitute the values

V=12\times \frac{4}{3}=16 V

I_1=\frac{V}{R_1}=\frac{16}{4}=4 A

I_1=I_2=I_3=4 A

Hence, current flows through any one of the resistors is 4 A.

7 0
3 years ago
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