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slega [8]
2 years ago
5

A train goes at 78kph for 20 minutes. How long does it travel?

Mathematics
2 answers:
DerKrebs [107]2 years ago
8 0

Answer:

26km

Step-by-step explanation:

The train can travel 78km per hour or per 60 min

78 = 60

x = 20

Cross multiply:

(78)(20) = 60x

1560 = 60x

x = 26

Thus the train travels 26km in 20 min

irina1246 [14]2 years ago
3 0

Answer:

<h2><u><em>26  km</em></u></h2>

<u><em></em></u>

Step-by-step explanation:

A train goes at 78kph for 20 minutes. How long does it travel?

  • 1 hour = 60 minutes
  • 20 minutes = 1/3 hour

so

78 * 1/3 =

<u><em>26  km</em></u>

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With a line 7 cm long. Use a set square and a ruler and draw perpendicular lines at both ends
Setler79 [48]

Answer:

See Explanation

Step-by-step explanation:

According to the Question,

Steps of construction:

  • Step I - Draw a line segment AB = 7 cm with the help ruler.
  • Step II - with vertex A, by using compass take more than half of AB and draw arcs, one on each side of AB.
  • Step III - with vertex B, by using a compass with the same length, cut the previous arcs at X and Y respectively.
  • Step IV - with help of the ruler join the points X and Y Thus XY is the perpendicular bisector of line AB.

(For Diagram please find in attachment)

5 0
3 years ago
Two student are reading a book. Keith reads 6 pages a day.tameka read 5 pages a day but he start sooner and has already read 15
NemiM [27]

Answer: Whoever read the 15 pages before read the most.


Step-by-step explanation:


6 0
4 years ago
An amount of $4000 was deposted in a bank of 7% compounded quarterly for 2 years. The rate the increased to 10% and was compound
GarryVolchara [31]

Answer:

  $5599.20

Step-by-step explanation:

The quarterly interest rate for the first two years was ...

  7%/4 = 0.0175

So, the multiplier each quarter for those 8 quarters was 1+0.0175 = 1.0175. At the end of the first 8 quarters, the account value had been multiplied by ...

  1.0175^8

For the next 8 quarters, the quarterly interest rate was 10%/4 = 0.025. So at the end of those 8 quarters, the balance had been multiplied by ...

  1.025^8

Then the balance at the end of 4 years was ...

  $4000(1.0175^8)(1.025^8) ≈ $5599.20

The balance was $5599.20.

6 0
3 years ago
ryan has a mix of action and sports games for a total of 39 video games his action collection is three more than half his sports
iVinArrow [24]

Answer:

He have <u>15</u> action games and <u>24</u> sports games.

Step-by-step explanation:

Given:

Ryan has a mix of action and sports games for a total of 39 video games his action collection is three more than half his sports collection.

Now, to find the number of action games and sports games.

Let the sports games be x.

As, given his action collection is three more than half his sports collection.

Thus, the action games = 3+\frac{x}{2} .

Total number of video games = 39.

So, we set an equation to get the number of action games and sports games:

x+(3+\frac{x}{2})=39

x+3+\frac{x}{2} =39

<em>Subtracting both sides by 3 we get:</em>

x+\frac{x}{2} =36

\frac{2x+x}{2}=36

\frac{3x}{2} =36

<em>Multiplying both sides by 2 we get:</em>

3x=72

<em>Dividing both sides by 3 we get:</em>

x=24.

<u>The sports games he have = 24.</u>

Now, to get the action games we substitute the value of x:

3+\frac{x}{2}

= 3+\frac{24}{2}

= 3+12

= 15.

<u>The action games he have = 15.</u>

Therefore, he have 15 action games and 24 sports games.

6 0
4 years ago
Assume that the weights of spawning Chinook salmon in the Columbia river are normally distributed. You randomly catch and weigh
s344n2d4d5 [400]

Answer: The point estimate for the mean weight of all spawning Chinook salmon in the Columbia River is the mean weight from your sample (\overline{x}) = 31.2 pounds .

Step-by-step explanation:

The weights of spawning Chinook salmon in the Columbia river are normally distributed.

Given :  The mean weight from your sample is 31.2 pounds with a standard deviation of 4.4 pounds.

The point estimate for the mean (\mu) weight of all spawning Chinook salmon in the Columbia River is the mean weight from your sample (\overline{x}) i.e. is 31.2 pounds because the best point estimate for population mean is the sample mean. [in normal distribution]

8 0
3 years ago
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