Answer:
96 g of O
Explanation:
Mg(OH)₂ → Magnesium hydroxide
Molar mass → 24.3g/mol . 1 + 16g/mol . 2 + 1g/mol . 2 = 58.3 g/mol
We determine the moles of hydroxide → 175 g . 1mol/58.3g = 3 moles
Let's make some rule of three:
In 100 g of compound we have 54.87 g of O
In 58.3 g of compound we may have (58.3 . 54.87) / 100 = 32 g
So, 1 mol of hydroxide has 32 g of oxygen
3 moles of hyroxide may have (3 .32)/1 = 96 g of O
Answer:
1. 36
2. Two
Explanation:
The Lewis structure shows the valence electrons present in a compound. Usually the valence electrons are shown as dot structures around the symbol of the elements involved in the compound.
For a compound AB4 where B is more electronegative than A and A has 8 electrons in its valence shell, there will be thirty six valence electrons on the outermost shell of the molecule.
There are six electron pair domains present in the molecule, four bond pairs and two lone pairs. The molecule is in a square planar geometry.
