When you wake up early, and go brush your teeth the toothpaste is made of chemical compounds, the water that you use to wash your faceis treated chemically. To make the coffee sugar or sweetener has chemical compounds.
Answer:
B
Explanation:
A is wrong because heat is what makes the process faster.
B is right because the finer grains are able to dissolve at a higher rate since the amount of one grain reduces it's time to dissolve.
C is wrong because simply adding more water will not increase or decrease the dissolving rate.
Answer:
1.208x10⁻³M and 392.5ppm La(NO3)3
Explanation:
The reaction that occurs is:
La2O3 + 6HNO3 → 2La(NO3)3 + 3H2O
Molarity is defined as the moles of solute (In this case, LaO3) per liter of solution. And ppm, are mg of solute per liter of solution.
To solve this question we must find the moles of La(NO3)3 produced and its mass in milligrams to find molarity and ppm:
<em>Moles La2O3 -Molar mass: 325.81g/mol-</em>
0.1968g * (1mol / 325.81g) = 6.04x10⁻⁴ moles La2O3
<em>Moles La(NO3)3:</em>
6.04x10⁻⁴ moles La2O3 * (2mol La(NO3)3 / 1mol La2O3) = 1.208x10⁻³ moles La(NO3)3
<em>Molarity:</em>
1.208x10⁻³ moles La(NO3)3 / 1L =
<h3>1.208x10⁻³M</h3>
<em>Mass La(NO3)3 -Molar mass: 324.92g/mol-</em>
1.208x10⁻³ moles La(NO3)3 * (324.92g / mol) = 0.392.5g La(NO3)3
In mg:
392.5mg La(NO3)3 / 1L =
392.5ppm La(NO3)3
Answer: Nitric acid + Sodium bicarbonate => Sodium nitrate + Water + Carbon dioxide
Explanation: The chemical equation is expressed in this exact reaction
HNO3 + NaHCO3 => NaNO3 + H2O + CO2
Answer:
0.174 M
Explanation:
The same can be solve by using Nernst's equation
The Nernst's equation is:
![Ecell=E^{0}_{cell}-\frac{0.0592}{n}log\frac{[anodic]}{[cathodic]}](https://tex.z-dn.net/?f=Ecell%3DE%5E%7B0%7D_%7Bcell%7D-%5Cfrac%7B0.0592%7D%7Bn%7Dlog%5Cfrac%7B%5Banodic%5D%7D%7B%5Bcathodic%5D%7D)
For silver cell
n= 1
As both the compartments have silver nitrate solution,t the standard emf of cell will be zero.
Given
Ecell = 0.045
[Anodic compartment]= 1 M
Putting values
Taking antilog and solving
[AgNO3]=0.174 M
