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trapecia [35]
2 years ago
7

What does group 16 (oxygen family) have in common

Chemistry
2 answers:
Dimas [21]2 years ago
7 0

Answer: here is your answer

Explanation:

The oxygen family consists of the elements that make up group 16 on the periodic table: oxygen, sulfur, selenium, tellurium, and polonium. These elements all have six electrons in their outermost energy level, accounting for some common chemical properties among them.

Marina86 [1]2 years ago
6 0

Answer:

they all have 6 valence electrons

Explanation:

all elements in group 16 have 6 valence electrons

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If another hydrogen of c2h5cl is replaced by a chlorine atom to yield c2h4cl2, how many isomers would result?
Mandarinka [93]

One isomer is formed

1,1- Dichloroethane is the isomer.

If another hydrogen of c2h5cl is replaced by a chlorine atom to yield c2h4cl2, it would result in one isomer.

  • In contrast to 1,2-dichloroethane, which has two chlorine atoms connected to distinct carbon atoms, 1,1-dichloroethane has two chlorine atoms bound to the same carbon atom.
  • Isomers are each of two or more compounds having the same formula but various atom arrangements in the molecule and unique characteristics.

<h3>What three types of isomers are there?</h3>
  • Chain isomers
  • Functional group isomers
  • Positional isomers

These are the three different categories of structural isomers.

<h3>How is an isomer recognized?</h3>
  • Their bonding patterns and the way they occupy three-dimensional space can be used to distinguish them.
  • Determine the bonding patterns of structural (constitutional) isomers.
  • Although the atoms in the compounds are the same, their connections create various functional groups.

<h3>What makes isomers significant?</h3>
  • Because two isomers might have the same chemical formula but different chemical structures, they are significant.
  • The molecule's properties are influenced by its structure.

To learn more about isomers visit:

brainly.com/question/12796779

#SPJ4

4 0
2 years ago
What group is the element barium(Ba) In?<br>A. 1<br>B. 6<br>C. 56<br>D. 4​
LenaWriter [7]
Ummmmmmmmmmm 56 yes 56
7 0
2 years ago
1.For the first ten reactions, write a balanced reaction for each tube in which a reaction occurred. If there was no reaction, w
slamgirl [31]

The equations of reaction occurring in the tubes are as follows:

  • 2 MnO₄⁻ + 6 Br⁻ + 8 H⁺ → 2 MnO₂ + 3 Br₂ + 4 H₂O
  • 2 MnO₄⁻ + 6 I⁻ + 8 H⁺ → 2 MnO₂ + 3 I₂ + 4 H₂O
  • No reaction
  • 2 Fe³⁺ + 2 I⁻ → 2 Fe²⁺ + I₂

<h3>What are the reactions occurring in the tubes?</h3>

The reactions occurring in the tubes are redox reactions.

Based on the table the equations of reaction are as follows:

  • 2 MnO₄⁻ + 6 Br⁻ + 8 H⁺ → 2 MnO₂ + 3 Br₂ + 4 H₂O
  • 2 MnO₄⁻ + 6 I⁻ + 8 H⁺ → 2 MnO₂ + 3 I₂ + 4 H₂O
  • No reaction
  • 2 Fe³⁺ + 2 I⁻ → 2 Fe²⁺ + I₂

In conclusion, redox reaction are reactions in which electrons are transferred.

Learn more about redox reactions at: brainly.com/question/26750732

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6 0
2 years ago
Mercury is the only metal that is a liquid at room temperature. When mercury vapor is inhaled, it is readily absorbed by the lun
Lapatulllka [165]

Answer:

P = 0.0166 mm Hg

Explanation:

To solve this question, we need to use the Clausius Clapeyron equation, which is a commonly used expression to calculate vapour pressure at a given temperature. We have the enthalpy of vaporization of the mercury, so, let's write the equation:

Clausius Clapeyron equation:

Ln (P₂ / P₁) = (-ΔHv / R)(1/T₂ - 1/T₁)    (1)

Where:

R: universal constant of gases (8.314 J / K.mol)

P₂: Vapour pressure at 43°C (or 316 K)

P₁: Pressure of mercury at the boiling point (1 atm)

T₂: temperature at 43 °C

T₁: Boiling point of mercury (357 °C or 630 K)

As we are given the boiling point of the mercury, we can safely assume that the pressure at this point is 1 atm, becuase remember that when a sustance boils, is because it's internal pressure has reached the atmospherical pressure of 1 atm. With this clear, all we just need to do is solve for P₂. We are going to do this very slowly so you can understand the process. First let's replace the given data:

Ln (P₂ / 1) = (-59100 J/mol / 8.314 J / K.mol) (1/316 - 1/630)

Ln P₂ = -7108.49 * (3.16x10⁻³ - 1.59x10⁻³)

Ln P₂ = -7108.49 * (1.51x10⁻³)

Ln P₂ = -10.7338

P₂ = 10⁽⁻¹⁰°⁷³³⁸⁾

P₂ = 2.18x10⁻⁵ atm

We can express this value in mm Hg and it will be:

P₂ = 2.18x10⁻⁵ * 760

<h2>P₂ = 0.0166 mm Hg</h2>

Hope this helps

8 0
2 years ago
The concentration of CI ion in a sample of H,0 is 15.0 ppm. What mass of CI ion is present in 240.0 mL of H,0, which has a densi
Doss [256]

Answer:

Mass of solute = 0.0036 g

Explanation:

Given data:

Concentration of Cl⁻ = 15.0 ppm

Volume of water = 240 mL

Mass of Cl⁻ present = ?

Solution:

1 mL = 1 g

240 mL = 240 g

Formula:

ppm = mass of solute / mass of sample ×1,000,000

by putting values,

15.0 ppm = (mass of solute / 240 g) ×1,000,000

Mass of solute = 15.0 ppm ×  240 g / 1,000,000

Mass of solute = 0.0036 g

8 0
3 years ago
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