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sasho [114]
3 years ago
8

Stretch y=5x vertically about the fixed x-axis by a factor of 2

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
3 0
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see

A = 2, then

y= 2(5)x ---> y = 10x
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3 0
3 years ago
2ci 1=-d 6-ci solve for c and d
Otrada [13]
Imaginary numbers ? just equate the imaginary with imaginary and real with real

<span>2ci 1=-d 6-ci <<< what the * is that ?

</span><span>
</span>
5 0
3 years ago
Two straight edges of a pizza slice meet at an angle of 30°. If the pizza has a radius of 12
melisa1 [442]

Answer:

<h3>area of the slice:      A = 12π in² ≈ 37.7 in² </h3><h3>lenght of its crust:  L = 24π in ≈ 6.28 in</h3>

Step-by-step explanation:

R = 12 in

360°:30° = 12

so the area of the slice is ¹/₁₂ of whole pizza

A = ¹/₁₂•πR² = ¹/₁₂•π•12•12 = 12π in² ≈ 37.7 in²

Crust is the perimeter of pizza so crust of the slice is ¹/₁₂ of the perimeter:

L = ¹/₁₂•2πR = ¹/₁₂•2π•12 = 2π in ≈ 6.28 in

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3 years ago
What is the solution for x in the equation? 4x − 3 + 5 = 2x + 7 − 8x
Ivan
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4 years ago
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Nonamiya [84]
Assuming you meant 2+3(67x34)=y
67x34=2278
2+3(2278)=y
5(2278) or 5x2278=y
y=11390
3 0
4 years ago
Read 2 more answers
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