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1 answer:
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Answer:
<em>The speed of the projectile when it impacts the ground is 1000 m/s</em>
Explanation:
<u>Vertical Launch</u>
When an object is launched vertically and upwards it starts to move at an initial speed vo, then the acceleration of gravity makes that speed to reduce until it reaches 0. The object has reached its maximum height. Then, it starts to move downwards in free fall, with initial speed zero and gradually increasing it until it reaches the ground level. We will demonstrate that the speed it has when impacts the ground is the same (and opposite) as the initial speed vo.
The speed when the object is moving upwards is given by
The time it takes to reach the maximum height is when vf=0, i.e.
solving for t
The maximum height reached is
Then, the object starts to fall. The object's height is given by
where t' is the time the object has traveled downwards. The height will be 0 again when
Solving for t'
We can see the time it takes to reach the maximum height is the same it takes to return to ground level. Of course, the speed when it happens is
Thus, the speed of the projectile when it impacts the ground is 1000 m/s
Complete Question
The diagram for this question is showed on the first uploaded image (reference homework solutions )
Answer:
The velocity at the bottom is
Explanation:
From the question we are told that
The total distance traveled is
The mass of the block is
The height of the block from the ground is h = 0.60 m
According the law of energy
Where PE is the potential energy which is mathematically represented as
substituting values
So
KE is the kinetic energy at the bottom which is mathematically represented as
So
substituting values
=>
=>
=>
