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notka56 [123]
3 years ago
8

What is meant by the term longitudinal wave?​

Physics
2 answers:
guajiro [1.7K]3 years ago
6 0

\underbrace{ \sf{Required \: Answer}} :

Longitudinal waves are those in which the particles of a medium vibrate to and fro in the direction of propagation of the wave through the medium. Sound wave is an example of longitudinal wave.

\text{Hope \: I \: helped!}

\text{Have \: a \: wonderful \: time!}ツ

~ \sf{TheAnimeGirl}

AnnZ [28]3 years ago
5 0

Answer:

a wave in which the direction of displacement is the same as the direction of propagation, as a sound wave.

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A solenoidal coil with 21 turns of wire is wound tightly around another coil with 350 turns. The inner solenoid is 22.0 cm long
Thepotemich [5.8K]

Answer:

(a)The average of magnetic flux trough each turns is 3.63 \times 10^{-8} wb.

(b) The magnitude of  mutual inductance of the two solenoid is 1.596 \times 10^{-5} H.

(c)The magnitude of emf induced in the outer solenoid by changing  current in the inner solenoid is 0.027132 v .

Explanation:

Given that,

The number of turns of the solenoid=N₁= 350

The diameter of the solenoid=D= 2.20 cm=0.022

The length of the solenoid is = l = 22.0 cm=0.22 m

The second solenoid with N_2= 21 turns which is wound around the solenoid at its center.

The current in the inner solenoid is I_1 = 0.150 A and is increasing at a rate of 1700 A/s i.e \frac{dI_1}{dt}= 1700 A/s

(a)

The formula of magnetic field of a solenoid is

B=\mu_0 nI=\frac{\mu_0 N_1I_1}{l}

                 =\frac{(4\pi \times 10^{-7} T.m/A) (350)(0.15 \ A)}{0.220 \ m}

                \approx 3.0 \times 10^{-4} T

So, the magnetic flux of each turns

\phi = BA=B \pi (\frac d2)^2

            =(3.0\times 10^{-4}\ T)\pi (\frac {0.022}{2} \ m)^2

             =1.14 \times 10^{-7}  wb

The average of magnetic flux trough each turns is 3.63 \times 10^{-8} wb.

(b)

Since the both coil wound tightly. So, the magnitude magnetic flux though each turns of both coils is same.

The mutual inductance of the two solenoid is

M=\frac{N_2\phi}{I_1}

     =\frac{(21)(1.14 \times 10^{-7}\ wb)}{0.15\ A}

    =1.596 \times 10^{-5} H

(c)

The formula of emf is

\varepsilon =-M\frac{dI_1}{dt}

  =-(1.596\times 10^{-5}\ H) (1700 \ A/s)

  =27.132 \times 10^{-3} v        

 =0.027132 v

 The emf induced in the outer solenoid by changing  current in the inner solenoid is 0.027132 v .    

4 0
3 years ago
The Coulomb force between two charges q1 and q2 at separation r in air is F. If half of the separation is filled with medium of
vodomira [7]

Answer:

The new Coulomb force is q₁q₂/9πε₀r²

Explanation

The coulomb force between the two charges q₁ and q₂ at a distance r in air is given by F = q₁q₂/4πε₀r².

Now, let us assume the material of dielectric constant κ = 9 is placed between them on the side of the q₁ charge. The value of its effective charge is now q₃ = q₁/κ at a distance of d = r/2 from the q₂ charge.

Since we have air between q₂ and q₃, the coulomb force between them is

F' = q₂q₃/4πε₀d²

= q₂(q₁/κ)/4πε₀(r/2)²

=  4q₂q₁/κ4πε₀r²

= 4/κ(q₂q₁/4πε₀r²)

= 4/9 × (q₂q₁/4πε₀r²)

= q₁q₂/9πε₀r²

So, the new Coulomb force is q₁q₂/9πε₀r²

3 0
4 years ago
2 Resistors of resistance, R = (100 +- 3) Ohm, R2 = (200+-4)Ohm are connected in Parallel and Series.
Orlov [11]

According to what I've learnt, in any expression of multiplication or division, the percentage errors of each term are added up to find the equivalent percentage error. That is, if

<span><span>y=<span>ABC
</span></span><span>
y=<span>ABC</span></span></span>then<span><span>% error in y= % error in A + % error in B + % error in C</span></span>

For the above problem, let <span><span>Rs</span></span> denote series combination. Then <span><span><span>Rs</span>=300±7</span></span> ohm.

Let <span><span>Rp</span></span> denote parallel combination.

<span><span>∴<span>Rp</span>=<span><span><span>R1</span><span>R2/</span></span><span><span>R1</span>+<span>R2 </span></span></span>= <span><span><span>R1</span><span>R2/</span></span><span>Rs</span></span></span></span>

Ignoring errors, we get <span><span><span>Rp</span>=<span>200/3 = </span></span></span><span><span>66.67</span></span> ohm

<span><span>%<span>error in R1</span>=3</span></span>, <span><span>%<span>error in R2</span>=2</span></span>, <span><span>%<span>error in Rs</span>=<span>7/3</span></span></span>

Hence, <span><span>%<span>error in Rp</span>=3+2+<span>7/3</span>=<span>22/3</span></span></span>

So, error in <span><span>Rp</span></span> will be <span><span><span>22/3</span>% of </span></span><span><span>200/3</span></span>, which is approximately <span>4.89.</span>

Hence, I got <span><span><span>Rp</span>=66.67±4.89</span></span> ohm.

However, the book used the formula described and proved here and arrived at the answer <span><span><span>Rp</span>=66.67±1.8</span></span>ohm.

8 0
3 years ago
Read 2 more answers
The center of the Milky Way galaxy lies in the direction of the _constellation, aboutlight-years away.
Elza [17]

Answer:

Sagittarius

Explanation:

The center of the Milky Way galaxy lies in the direction of the Sagittarius constellation, about 26,000 light-years away.

5 0
4 years ago
Read 2 more answers
Calculate the amount of energy produced in joules by 100- watt light bulb lit for 2.5 hours.
9966 [12]
100/2.5 is 40.
40 is the energy that is being produced 
4 0
4 years ago
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